- #1

shinto1

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**1. Determine the equation y=f(x) for each of the following cases in simplest form. All of the plots are straight lines and all coordinates are indicated with abscissa first, ordinate second (x,y).**

-log y versus log x on a rectilinear graph passes through (5,7) and (2,3)

-(y-2)^2 versus x on a log-log graph passes through (1,2) and (3,4)

-√y versus x on a semi-log graph passes through (3,2) and (6,4)

-log y versus log x on a rectilinear graph passes through (5,7) and (2,3)

-(y-2)^2 versus x on a log-log graph passes through (1,2) and (3,4)

-√y versus x on a semi-log graph passes through (3,2) and (6,4)

**2. Homework Equations**

-Power Equation : y = bx^m

-Linear Equation: y = mx +b

-Exponential Equation: y = be^mx or y = b10^mx (e is base 10)

-Point slope formula: y-y1 = m(x-x1)

-Power Equation : y = bx^m

-Linear Equation: y = mx +b

-Exponential Equation: y = be^mx or y = b10^mx (e is base 10)

-Point slope formula: y-y1 = m(x-x1)

**3. For the first problem, I found the slope, m, which is 4/3 (or 1.333) and then I used the point slope formula to get y = 1.333x + 0.35. This equation is in a linear format but the thing that confuses me is the "log y versus log x". I used this same process for the other problems but I'm still confused by the "(y-2)^2 versus x on a log-log graph" and**

√y versus x on a semi-log graph". I really don't understand how to implement that part of the question into the solution, so any help would be appreciated.√y versus x on a semi-log graph". I really don't understand how to implement that part of the question into the solution, so any help would be appreciated.