How Does Binding Energy Affect Nuclear Fission Reactions?

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Homework Help Overview

The discussion revolves around a nuclear fission reaction involving uranium-236 and its products, specifically focusing on the binding energy and its implications for stability and energy release in nuclear reactions.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are analyzing the validity of statements regarding the fission reaction and the properties of the resulting fragments, questioning the relationships between atomic mass, atomic number, and binding energy.

Discussion Status

Some participants have provided feedback on the original poster's reasoning, indicating that certain assumptions may be incorrect. There is ongoing exploration of the implications of binding energy on stability and energy release, with some clarity emerging around the definitions of atomic mass and atomic number.

Contextual Notes

Participants are working with a provided graph of binding energy per nucleon and are navigating potential misunderstandings regarding the definitions of Z and A in the context of nuclear reactions.

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Homework Statement


Consider the fission reaction in which 236U92 breaks up into 141Ba56 and 3 neutrons and an unknown fragment. Which of the following statements are true about this fission reaction in particular and nuclear reaction energies in general? You are given a plot of the binding energy (BE) per nucleon to help you.
http://aycu17.webshots.com/image/25736/2004649007142429776_rs.jpg

True False the unknown fission fragment will have Z = 33
True False the unknown fission fragment will have A = 95
True False a heavy nucleus (like uranium) can become more stable via a reaction that moves it back to the left on the BE curve
True False a heavy nucleus (like uranium) releases less energy in a single fission reaction than in one alpha decay
True False the fission products (two fragments plus 3 neutrons) have less total mass than the original 236U

The Attempt at a Solution



1. Z= Atomic Mass so true; must be equal before and after the equation
2. A= Atomic # so true; must be equal before and after the equation
3. Not sure, i thikn its false because of the graph, not sure about this one
4. Also not sure about this, but believe false, because it has alpha decay.
5. The total mass must be equal before and after the reaction

My answers are in bold, and above are my reasons, i can't figure out what I am doing wrong. Can anyone help?

Thanks
 
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I think you have one and two right. I think 3 is True because higher binding energy -> more stability...

Not sure about 4.

But 5 is true... right side has lower mass because energy has been released...
 
Turns out 1 and 2 are false?? Any1 have any clue why? that makes no sense
 
Oops... sorry A = 92... 236-141-3... and Z = 36 (92-56)

A is the total number of protons+neutrons.
Z is the total number of protons.

I was mixing up number of protons and neutrons...

So yes, they're false.
 

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