Is Local the Same as Isotropic in Physics?

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Discussion Overview

The discussion revolves around the relationship between local and isotropic properties in physics, particularly in the context of mathematical expressions involving integrals. Participants explore whether local expressions can be equated with isotropic behavior, specifically questioning if isotropy implies translational invariance.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant, Niles, presents two expressions and suggests that the second expression, F', is local in space and questions if it describes an isotropic object.
  • Niles asks if isotropic can be equated with translational invariance.
  • Another participant requests definitions for the symbols used in the expressions to clarify the physics context.
  • A subsequent reply seeks clarification on additional symbols, indicating a need for further definition of the terms involved.

Areas of Agreement / Disagreement

The discussion does not reach a consensus, as participants are still defining terms and exploring the implications of local versus isotropic properties.

Contextual Notes

Limitations include the lack of definitions for all symbols involved, which may affect the clarity of the discussion and the understanding of the relationships being proposed.

Niles
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Hi

Say I have two expressions of the form

[tex] F(r, t) = \int{dr'\,dt'\,\,x(r,r',t,t')g(r',t')}[/tex]

and

[tex] F'(r, t) = \int{dt'\,\,x'(r,t,t')g'(r, t')}[/tex]

It is clear that F' is local in space, whereas F is non-local in space. Is it correct of me to say that F' describes an isotropic object? I.e., does isotropic = translational invariance?


Niles.
 
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You should define the various symbols to make it a physics question. Right now they are mathematical expressions.
 
Good point, thanks. Say "x" denotes the susceptibility and "g" the electric field.
 
How about r, r', t, and t'.
 

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