Is Momentum Conserved in a Collision Between Two Unequal Masses?

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SUMMARY

In the collision between Ball A (2 kg, 0.5 m/s) and Ball B (3 kg, stationary), momentum is conserved. The initial momentum (P1) is calculated as P1 = (2 kg * 0.5 m/s) + (3 kg * 0) = 1 kg·m/s. After the collision, the final momentum (P2) is P2 = (2 kg * 0.1 m/s) + (3 kg * 0.3 m/s) = 1 kg·m/s. Since P1 equals P2, momentum is conserved in this system.

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Ball A, which weighs 2 kilograms, is moving at 0.5 meters/second and strikes stationary Ball B at the direct center of the ball.
Ball B, which weighs 3 kilograms, moves off at 0.3 meters/second and in the same original direction Ball A was moving. Ball A continues to move forward, but only at 0.1 meters/second. Is momentum conserved? Explain.I don't even know where to start, or what to do so could I have some help with this?
 
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The momentum of the system is conserved if it's the same before the strike and after...
What's the momentum before?
What about after?
 
The system consists of two bodies: ball A and ball B
All the movements are performed along one axis: OX. Let the positive direction coincide with the direction of ball A movement.
Then, the momentum before the strike
P1 = mAvA + mBvB
vA = 0.5 m/s, vB = 0
The momentum after strike
P2 = mAuA + mBuB
uA = 0.1 m/s, uB = 0.3 m/s

So, the conclusion is clear but still up to you)
 

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