PeterDonis said:
The "dip" is for the case where the photons arrive at exactly the same time at the swap beam splitter. And if they do so, as you say, they both come out the same output port. But if they do that, they can only swap into a limited number of the possible Bell states. In particular, they can't swap into the singlet state, which is the one in which we have one photon coming out each output port of the swap beam splitter. But that is the case that I am interested in doing an MZI analysis for. It is also the only case for which the "event ready" signal occurs in at least one of the entanglement swapping experiments you have referenced in the various threads we have had on that topic.
In other words, unless I'm missing something, the "dip" point, where the photons arrive at the swap beam splitter at exactly the same time, cannot be the only case where a swap occurs, and therefore cannot be the only case in which there is indistinguishability. There must be a finite window of time within which, if both photons arrive at the swap beam splitter, a swap can occur.
I. Mmmm, let's make sure we are saying the same thing. There are 2 completely different Bell states being applied in the experiment:
i) The Bell state for entangled photons 1 & 2, and the Bell state for entangled photons 3 & 4. These are normally chosen to the be same state. That is of course a function of the source, which in this case is PDC. And you are quite correct, for this experiment, the source pairs are created in the singlet state. That being the |ψ−> Bell state. The choice of this for the source Bell state is mostly a matter of convenience. I think we agree here just fine.
ii) The Bell state for entangled photons 1 & 4 applies of course only if a swap occurs. That can be any one of 4 possible Bell states |ψ+>, |ψ−>, |φ+>, |φ->. However, only 2 of the 4 can be detected/differentiated by detector clicks at the BSM (for photons 2 & 3 arriving nearly coincident). The 2 that can be distinguished are |ψ+> and |ψ−>. These 2 allow for 4 fold coincidences. The other 2 Bell states (|φ+>, |φ->) are ignored because they only yield 3 fold coincidences (since Photons 2 & 3 end up in the same detector and only appear as a single click). Only 4 fold coincidences are considered, because the specific detectors that go "click" differentiate between |ψ+> and |ψ−> for Photons 2 & 3. These always occur with one H> click and one V> click. I think we agree here as well.
If those 2 clicks occur in the same output port of the beam splitter (BS), then the resulting Bell state is |ψ+>. If those 2 clicks occur in different output ports of the beam splitter (BS), then the resulting Bell state is |ψ->. At this point, it doesn't matter whether the Bell state chosen for i) is the singlet state or not. What matters is that the 2 identified states are |ψ+> or |ψ−>.
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II. I am sure you are aware of all this, so let's re-examine the HOM dip. This is telling us that the Bell state is not being discriminated, and the singlet output state experiences destructive interference within the beam splitter during an H-O-M test.
That is exactly as you said above. You are wanting to present the analysis of the swapping experiment for just that case I guess, although I don't see why. Everything works exactly the same under every interpretation whenever there are 4 fold coincidences. Indistinguishability is a requirement regardless.
The fact that the arrival times for the H-O-M effect to appear is quite narrow means these two photons ARE interacting inside the BS. There is no way to reverse destructive interference. There is no way to distinguish the output photons once indistinguishable - even if you later attempt to check their polarization. Because if you knew (or could know) their polarization going into the BS, they wouldn't be indistinguishable, right?
So let's say we look at the singlet |ψ−> pairs coming out of your MZI. You are basically saying that they are orthogonally polarized (that's the hallmark, right)? That case can be identified, as easily as |ψ+>, which is also orthogonally polarized. So I say everything that applies to one case applies to the other.
I think what you are alluding to that the coincidence window for H-O-M effect (1-10 ps) is much smaller than the window for the swapping experiments (1-10 ns). I'm not sure I understand why those scales are so different, but I would guess it is related to the photon sources being independent and phase linked in some manner.
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III. We still have the following in the swapping scenario for MWI:
a) Some window during which the 2 & 3 photons must overlap at the BS, and be swapped into 1 of 4 possible states. That is not reversible. Coincident with the 4 possible Bell states, there are 2 permutations for each (reflected/transmitted) . There must be MWI branching into 8 worlds here.
b) The subsequent distance to the PBS can be any length. However, in principle a polarization measurement is reversible. Ignoring that, each of the above 8 worlds can be expressed 2 ways in polarization terms. That's 16 worlds by my count.
c) The final distance to the detectors can be any distance as well. I don't see the detectors as being the spot where the branching must occur. Again, that ordering can be arbitrary.
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IV. So I think we end up with a lot of issues for MWI to explain: when/where exactly is branching to occur per MWI? To be fair, QM is not exactly overly specific either - it just says look at the entire context. But QM does not specify observables have specific values at all times, which MWI apparently does make that claim. So when and where do those values change (discontinuously) if not at branching?