jbergman said:
Here is the comment I made that started this discussion
That post was in response to
@gentzen, not to me. Your post in response to me was:
jbergman said:
I think that is too narrow of an interpretation. IMO, the wave function should be considered hidden, hence, it's state is a hidden variable.
And I disagreed with that:
PeterDonis said:
On this view, every QM interpretation is a hidden variable interpretation, since QM itself, independent of any interpretation, is a hidden variable theory. Which makes the term "hidden variable" useless, since the whole point of the term was to distinguish between QM interpretations.
And then you went off on a tangent about Bell's work. Your claim that the wave function should count as a "hidden variable" has nothing to do with Bell's work.
jbergman said:
So really the dispute boils down to whether or not you consider the QM wave function hidden or not.
Yes, and I said no, for the reason I gave in the post of mine that I quoted above. If you want to respond to
that argument, by all means do so. But the argument I made has nothing to do with Bell's work. It's a simple argument about whether you want the term "hidden variable" to be useful in distinguishing between QM interpretations, or not.
jbergman said:
This question isn't of great import, though, to the main point, which is that QM is not embeddable in a local causal theory.
I have not disagreed with that at all, for the definition of "local causal" that you are using (in which a "local causal" theory would not be able to violate the Bell inequalities). As I commented in response to
@Morbert, though, I think one needs to be clear that this definition of "local causality" is
not the same as the one that is used by the relativistic QFT community; to that community, relativistic QFT
is "locally causal", because spacelike separated operators commute.
jbergman said:
I stand by my characterization of the quantum state vector as unobservable and "hidden".
It's not a direct observable, no, although quantum tomography can in principle pin it down to any desired degree of accuracy given enough repetitions of a particular preparation procedure.
"Hidden" in the sense of "hidden variable interpretation" would, as I said, make that term useless, since by this definition
every QM interpretation is a "hidden variable interpretation" since QM itself is a "hidden variable theory". If you want to use such a definition, I can't stop you, but I don't see the point.