Is my integration of e^-x/(1-e^-1) correct?

[willoconley]

It's been awhile since I've used integration, I guess I am a bit rusty with the calculus. I need to integrate:

e^-x / 1-e^-1 dx

1 / 1-e^-1 is pulled out of the integral and the integral of e^-x = -e^-x. So:

e^-x / 1-e^-1 dx = -e^-x / 1-e^-1

Could someone tell me if that is correct?

 

[JG89]

Looks good to me. Remember, you could always check your answer by taking the derivative of the antiderivative.