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physgrl
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Homework Statement
A 200-turn solenoid is 20.0 cm long and carries a current of 3.25 A. Find the magnetic field. Find the force exerted on a 15.0 µC charged particle moving at 1050 m/s through the interior of the solenoid, at an angle of 11.5° relative to the solenoid’s axis.
Homework Equations
r=mv/qB
torque=IABn (n=turns)
B=(μo/2π)*I/r
F=ILBsin(θ)
F=qvBsin(θ)
The Attempt at a Solution
n=200
l=.2m
I=3.25A
If I want to use torque=IABn to find B I need torque and I do not know how to find it with the length only. The second part I understand once I find the Magnetic Field, but I don't get how to find it with the info given.
the answer key says: B=4.08 x 10-3 T and F=1.28 x 10-5 N