Is My Solution for Magnetic Field and Force Correct?

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SUMMARY

The discussion centers on the correctness of a solution involving magnetic fields and forces, specifically using the equations F=qvB and R=mv/eB. The magnetic force calculated was 4.8x10^-14 N, and the radius of curvature was determined to be 1.90 x 10^-3 m. While the calculations for the magnetic force and radius are confirmed as correct, the time spent calculation was incorrect due to misunderstanding the arc length versus the circumference. Additionally, the direction of electron movement in the magnetic field was identified as potentially incorrect, necessitating a review of the problem statement.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically Lorentz force law.
  • Familiarity with the concepts of magnetic flux density and its direction.
  • Knowledge of kinematic equations related to circular motion.
  • Ability to perform vector cross products in three dimensions.
NEXT STEPS
  • Review the concept of the Lorentz force and its application in magnetic fields.
  • Learn about the implications of magnetic flux density direction on particle motion.
  • Study the differences between arc length and circumference in circular motion calculations.
  • Explore the effects of charge polarity (electrons vs. positrons) on motion in magnetic fields.
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Students studying electromagnetism, physics educators, and anyone involved in solving problems related to magnetic forces and particle motion in magnetic fields.

bckcookie
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Homework Statement



As attached file! Please advise me my solution is right or not! Thanks a lot!

Homework Equations



F=qvB - (1)
R=mv/eB
d/t = v
length of arc = 2pi(R)
sinθ=a/c

The Attempt at a Solution



a) the magnetic force,
F = qvb
=1.6x10^-19 x 10^7 x 0.03N
= 4.8x10^-14N
(does it need to product with sin 45degree?? please advise!)

b) the radius of curvature
R = mv/eB
= (9.11 x 10^-31kg x 10^7) / 1.6x10^-19 x 0.03
=1.90 x 10^-3m

c) The time spend
=The length of arc / v
= 2∏R / v
= 1.194 x 10^-9s

d) the distance of x
= 2Rsin45
= 2.687 x 10^-3 m
 

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bckcookie said:

Homework Statement



As attached file! Please advise me my solution is right or not! Thanks a lot!

Homework Equations



F=qvB - (1)
R=mv/eB
d/t = v
length of arc = 2pi(R)
sinθ=a/c

The Attempt at a Solution



a) the magnetic force,
F = qvb
=1.6x10^-19 x 10^7 x 0.03N
= 4.8x10^-14N
'Looks right! :approve:
(does it need to product with sin 45degree?? please advise!)
Think about what the cross product means. The magnitude of \vec A \times \vec B is the full AB only if \vec A and \vec B are perpendicular. Is the velocity perpendicular to the magnetic field? (Hint: you need to think in three dimensions. :wink:)
b) the radius of curvature
R = mv/eB
= (9.11 x 10^-31kg x 10^7) / 1.6x10^-19 x 0.03
=1.90 x 10^-3m
'Looks right. :approve:
c) The time spend
=The length of arc / v
= 2∏R / v
= 1.194 x 10^-9s
Try that one again. 2πR is the circumference of an entire circle of radius R, not just an arc length.
d) the distance of x
= 2Rsin45
= 2.687 x 10^-3 m
'Looks right to me. :approve:
 
By the way, I just noticed that something is not quite right with the problem statement. Either that, or it's a "trick" question. You might want to tell you instructor about this.

According to attached figure, the magnetic flux density is going into the page (denoted by the 'x's). That, combined with the direction and orientation of the arrows, and the fact that electrons are negatively charged, the electrons would not curl around in a counter-clockwise direction as the problem indicates. Instead, they would curl around in a clockwise direction, and exit the magnetic field at some distance x *below* where they entered -- not above.

Either the figure needs to be redrawn to show the magnetic field coming out of the page, OR the magnetic flux density should be changed from 0.03 T to -0.03 T, OR the direction of the arrows need be to be reversed, OR the electrons should be replaced with positrons.

Keeping everything as it is, x will end up being negative, thus you'll have to redo parts c) and d).
 
you are right! Thanks for your hints!
 

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