Is My Solution to This Exact Differential Equation Correct?

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SUMMARY

The discussion revolves around solving the exact differential equation represented by the system of partial derivatives: ∂f/∂x = x cos(y) + x² + y and ∂f/∂y = x + y² - (1/2)x² sin(y). The user correctly identifies that the system is exact, as the partial derivatives satisfy the condition ∂²f/∂y∂x = ∂²f/∂x∂y. The solution is implicitly defined by f(x, y(x)) = C, and the discussion emphasizes the importance of understanding exact equations in ordinary differential equations (ODEs).

PREREQUISITES
  • Understanding of partial derivatives and their applications in differential equations
  • Familiarity with exact differential equations and their properties
  • Knowledge of the Cauchy-Riemann equations and their significance in mathematical analysis
  • Basic integration techniques for solving ordinary differential equations
NEXT STEPS
  • Review the concept of exact differential equations in your textbook
  • Study the theorem related to the solution of exact equations and practice examples
  • Explore the relationship between exact equations and the Cauchy-Riemann equations
  • Practice solving various ordinary differential equations to strengthen integration skills
USEFUL FOR

Mathematics students, educators, and anyone interested in solving ordinary differential equations, particularly those focusing on exact equations and their applications in advanced calculus.

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Homework Statement
(x cos(y) + x^2 +y ) dx + (x + y^2 - (x^2)/2 sin y ) dy = 0
Relevant Equations
(x cos(y) + x^2 +y ) dx = - (x + y^2 - (x^2)/2 sin y ) dy
(x cos(y) + x2 +y ) dx = - (x + y2 - (x2)/2 sin y ) dy
I integrated both sides
1/2x2cos(y) + 1/3 x3+xy = -xy - 1/3y3+x2cos(y)

Then
I get x3 + 6xy + y3 = 0

Am I doing the calculations correctly?
Do I need to solve it in another way?
 
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You are looking for a function f(x,y) such that <br /> \begin{align*}<br /> \frac{\partial f}{\partial x} &amp;= x \cos(y) + x^2 +y \\<br /> \frac{\partial f}{\partial y} &amp;= x + y^2 -\frac12 x^2 \sin y<br /> \end{align*} The solution is then given implicitly by f(x,y(x))) = C.

Are you familiar with how to solve such a system?
 
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pasmith said:
You are looking for a function f(x,y) such that <br /> \begin{align*}<br /> \frac{\partial f}{\partial x} &amp;= x \cos(y) + x^2 +y \\<br /> \frac{\partial f}{\partial y} &amp;= x + y^2 -\frac12 x^2 \sin y<br /> \end{align*} The solution is then given implicitly by f(x,y(x))) = C.

Are you familiar with how to solve such a system?
Then do I have to solve two different differential equations?
 
the first thing i notice is that if i take the partial of the first equation with respect to y it is equal to the partial of the second equation with respect to x. I think this means the system is "exact". My differential equations are a bit rusty. To solve this system, you may need to review exact equations in yout textbook,
 
mpresic3 said:
the first thing i notice is that if i take the partial of the first equation with respect to y it is equal to the partial of the second equation with respect to x. I think this means the system is "exact". My differential equations are a bit rusty. To solve this system, you may need to review exact equations in yout textbook,
Correct. It implies there is f(x,y) with f_x , f_y equal to the respective equations.
 
This is a class of ODE known as exact equations in this text

Here is the theorem that gives the solution and a corresponding example from the text
Screen Shot 2021-04-20 at 12.33.11 AM.png

Screen Shot 2021-04-20 at 12.33.22 AM.png

once you get the hang of the process it becomes pretty simple actually.
 
docnet said:
This is a class of ODE known as exact equations in this text

Here is the theorem that gives the solution and a corresponding example from the textView attachment 281782
View attachment 281783
once you get the hang of the process it becomes pretty simple actually.
I always wondered if it is a coincidence that these are precisely the Cauchy-Riemann equations.
 

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