Is My Solution to This Exact Differential Equation Correct?

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Homework Help Overview

The discussion revolves around a differential equation presented in the form of an exact equation. The original poster attempts to verify their integration and solution process, questioning whether their calculations are correct and if an alternative method is necessary.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conditions for exactness of the differential equations, with some noting the relationship between the partial derivatives. Questions arise regarding the necessity of solving two different equations and the familiarity with the method of solving such systems.

Discussion Status

Several participants provide insights into the nature of the equations, confirming that the system is exact and suggesting a review of relevant textbook material. There is an acknowledgment of the theorem related to exact equations, but no consensus on the original poster's calculations has been reached.

Contextual Notes

Participants mention the need to review exact equations and the original poster's uncertainty about their approach. There is a reference to the Cauchy-Riemann equations, indicating a potential connection that is not fully explored.

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Homework Statement
(x cos(y) + x^2 +y ) dx + (x + y^2 - (x^2)/2 sin y ) dy = 0
Relevant Equations
(x cos(y) + x^2 +y ) dx = - (x + y^2 - (x^2)/2 sin y ) dy
(x cos(y) + x2 +y ) dx = - (x + y2 - (x2)/2 sin y ) dy
I integrated both sides
1/2x2cos(y) + 1/3 x3+xy = -xy - 1/3y3+x2cos(y)

Then
I get x3 + 6xy + y3 = 0

Am I doing the calculations correctly?
Do I need to solve it in another way?
 
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You are looking for a function f(x,y) such that <br /> \begin{align*}<br /> \frac{\partial f}{\partial x} &amp;= x \cos(y) + x^2 +y \\<br /> \frac{\partial f}{\partial y} &amp;= x + y^2 -\frac12 x^2 \sin y<br /> \end{align*} The solution is then given implicitly by f(x,y(x))) = C.

Are you familiar with how to solve such a system?
 
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pasmith said:
You are looking for a function f(x,y) such that <br /> \begin{align*}<br /> \frac{\partial f}{\partial x} &amp;= x \cos(y) + x^2 +y \\<br /> \frac{\partial f}{\partial y} &amp;= x + y^2 -\frac12 x^2 \sin y<br /> \end{align*} The solution is then given implicitly by f(x,y(x))) = C.

Are you familiar with how to solve such a system?
Then do I have to solve two different differential equations?
 
the first thing i notice is that if i take the partial of the first equation with respect to y it is equal to the partial of the second equation with respect to x. I think this means the system is "exact". My differential equations are a bit rusty. To solve this system, you may need to review exact equations in yout textbook,
 
mpresic3 said:
the first thing i notice is that if i take the partial of the first equation with respect to y it is equal to the partial of the second equation with respect to x. I think this means the system is "exact". My differential equations are a bit rusty. To solve this system, you may need to review exact equations in yout textbook,
Correct. It implies there is f(x,y) with f_x , f_y equal to the respective equations.
 
This is a class of ODE known as exact equations in this text

Here is the theorem that gives the solution and a corresponding example from the text
Screen Shot 2021-04-20 at 12.33.11 AM.png

Screen Shot 2021-04-20 at 12.33.22 AM.png

once you get the hang of the process it becomes pretty simple actually.
 
docnet said:
This is a class of ODE known as exact equations in this text

Here is the theorem that gives the solution and a corresponding example from the textView attachment 281782
View attachment 281783
once you get the hang of the process it becomes pretty simple actually.
I always wondered if it is a coincidence that these are precisely the Cauchy-Riemann equations.
 

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