Is Planck's Constant Irrational?

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The discussion centers on whether Planck's constant is irrational, with participants noting that its classification depends on how it is defined and measured. In SI units, Planck's constant is subject to experimental uncertainty, making its rationality indeterminate. Some argue that constants defined in specific units can be rational or irrational, depending on the context. The conversation also touches on the nature of physical quantities and the implications of defining constants, suggesting that exact values are necessary for categorization. Ultimately, the consensus is that without precise measurement, the rationality of Planck's constant remains unresolved.
  • #31
LeonhardEuler said:
If you add atoms one by one, you will probably come to a point where you have slightly less than 12g, and if you add one more atom you will have slightly more.

That's exactly what I was thinking. Atoms' masses are so small so we have no practical way of measuring so precisely, but I don't see a reason to believe that a whole number of 12C happens to weigh exactly 12 g. It could be that the closest one can get is barely under or barely over exactly 12 grams by half the mass of a neutron or any other small, positive number. And since it's nigh impossible to get two 12-gram samples of 12C with exactly the same percentage of isotopes, Avogadro's number will vary from sample to sample, which I hadn't thought of before...
 
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  • #32
If one defines units of measure on phyisical observations (as the speed of light), then yes it is possible to exactly know what the constant equals (since one is using the constant as the new "yard stick")

And I can see Avogardo's number being defined some day to be so many atoms of standard C12 atoms (or some other standardizable atom) - and define the kilogram to be so many of those. This completely changes the conversation though.

Of course, there is always the issue as to whether all neutrons weigh the same etc.

But we digress. Some constants are rational, some aren't.

--Elucidus
 

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