Is \(\psi(x) = \frac{1}{x^{\alpha}}\) in Hilbert Space?

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Homework Help Overview

The discussion revolves around the function \(\psi(x) = \frac{1}{x^{\alpha}}\) and its membership in a Hilbert space. Participants are examining the conditions under which this function satisfies the requirements for inclusion in a Hilbert space, particularly focusing on the integral properties of the function.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to determine the values of \(\alpha\) for which the integral of \(\psi^{2}\) converges. Questions have been raised regarding the proper formulation of the problem, including the domain of \(\psi(x)\) and the implications of singularities in the function.

Discussion Status

The discussion is ongoing, with participants clarifying the problem statement and exploring the implications of different values of \(\alpha\). Some guidance has been offered regarding the need to specify the domain of the function, and there is recognition of the potential issues related to singularities.

Contextual Notes

There is mention of the integral being evaluated from negative infinity to infinity, and concerns about the function's behavior at singular points, particularly at \(x = 0\) and as \(x\) approaches infinity.

zhaiyujia
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[SOLVED] Hilbert Space

Homework Statement


For What Values of [tex]\psi(x)=\frac{1}{x^{\alpha}}[/tex] belong in a Hilbert Sapce?

Homework Equations


[tex]\int x^{a}=\frac{1}{a+1} x^{a+1}[/tex]

The Attempt at a Solution


I tried to use the condition that function in Hilbert space should satisfy:
[tex]\int\psi^{2}=A[/tex] but it seems always infinite exist in x=0 or x=infinite
 
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Why are you writing the integral of x^a, when you want to examine the integral of 1/x^{2a}?

Also, have you written down the question completely? What is the domain on which [itex]\psi(x)[/itex] is defined?
 
one is alpha and another is a. I just write a integral equation, a = 2*alpha. I think it is not the key point. The question is complete. I asked my professor if there is some constrain of x, she said x can be any value. that is to say the integral will from minus infinite to infinite
 
zhaiyujia said:
one is alpha and another is a.
Okay, they both looked the same to me.
The question is complete.
It can not be. There's at least a couple of missing words. Here's one way to write a somewhat more complete question:

For what values of [itex]\alpha[/itex] does [itex]\psi(x)=1/{x^{\alpha}}[/itex] belong in a Hilbert space?

I asked my professor if there is some constrain of x, she said x can be any value. that is to say the integral will from minus infinite to infinite
This needs to be specified in the question. You have not completely specified a function unless you describe its domain.
 
Thanks, I explained it in the interval of minus infinite to minus zero and zero to infinite. I guess a wave function with singularity is not a good one in physic...
 

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