Is Riemann's Zeta at 2 Related to Pi through Prime Numbers?

[bland]

TL;DR

How in the hell can a mere mortal come to grasp this madness.

I just saw that one of the ways of calculating Pi uses the set of prime numbers. This must sound crazy even to people who understand it, is it possible that this can be explained in terms that I, a mere mortal can understand or it is out of reach for non mathematicians?

 

[sysprog]

There is more than one way of calculating the value of $\pi$ using prime numbers. Which one did you have in mind?

 

[bland]

For the purposes of my question it doesn't really matter which one, I'm just utterly bewildered where the connection is. What is the connection between using numbers that can only be divided by themselves or one, in other words numbers that are not divisible by any number other than the trivial cases, and a circle.

However it was this one that I saw...

 

[PeroK]

For the purposes of my question it doesn't really matter which one, I'm just utterly bewildered where the connection is. What is the connection between using numbers that can only be divided by themselves or one, in other words numbers that are not divisible by any number other than the trivial cases, and a circle.

This is what excites many people about mathematics. These extraordinary deep connections.

 

[Hornbein]

For the purposes of my question it doesn't really matter which one, I'm just utterly bewildered where the connection is. What is the connection between using numbers that can only be divided by themselves or one, in other words numbers that are not divisible by any number other than the trivial cases, and a circle.

However it was this one that I saw...

But nine isn't a prime number.

 

[jedishrfu]

Nor is 15.

 

[FactChecker]

But nine isn't a prime number.

He gets to the prime number part later.

 

[Mark44]

But nine isn't a prime number.

Nor is 15.

Prime in the sense of "not divisible by 2."

 

[Vanadium 50]

However it was this one that I saw...

9 is not prime. 15 is not prime. 2 is prime and is missing. Those are the odd numbers.

 

[Vanadium 50]

However, there are primes in the decimal expansion,
3 is prime.
14159 is prime.
2 is prime.
653 is prime.

 

[PeroK]

However, there are primes in the decimal expansion,
3 is prime.
14159 is prime.
2 is prime.
653 is prime.

It's possible that all primes numbers are in there somewhere! And, in fact, that all finite sequences are in there.

https://www.askamathematician.com/2...that-it-exists-somewhere-in-the-digits-of-pi/

 

[Hornbein]

It's possible that all primes numbers are in there somewhere! And, in fact, that all finite sequences are in there.

https://www.askamathematician.com/2...that-it-exists-somewhere-in-the-digits-of-pi/

Aha. Every prime number is in the decimal expansion of pi with probability one. But does this prove every prime number is in the decimal expansion of pi? I'm inclined to think not. It appears that this mathematician also says not, and that no proof is known. You might be able to show that it is so with probability one, but that isn't a proof.

 

[PeroK]

Aha. Every prime number is in the decimal expansion of pi with probability one. But does this prove every prime number is in the decimal expansion of pi? I'm inclined to think not. It appears that this mathematician also says not, and that no proof is known. You might be able to show that it is so with probability one, but that isn't a proof.

There's probability of one that you are misunderstanding something here!

 

[FactChecker]

To everyone who comments that the initial screenshot of the video contains non-primes, please watch the video. After the first few minutes, the video is about a series of primes.

 

[Vanadium 50]

My point/joke was that you might break pi's decimal expansion into a concatenation of primes. I am not sure if this is true.

 

[BWV]

From Wikipedia, here is the square root of 2

e has an even simpler series representation

But is the reverse true - does any given transcendental or real number have a series representation using only integer ratios?

 

[TeethWhitener]

From Wikipedia, here is the square root of 2

e has an even simpler series representation

But is the reverse true - does any given transcendental or real number have a series representation using only integer ratios?

Trivially, we have
$$0.a_1a_2a_3\ldots a_i=\sum_{i>0}{\frac{a_i}{10^i}}$$
where each $a_i$ is an integer. We also have that the rationals are dense in the reals, meaning that any real number can be approximated arbitrarily accurately by the rationals. So the answer to your question as posed seems to be yes. Did you have something different in mind?

 

[bland]

To everyone who comments that the initial screenshot of the video contains non-primes, please watch the video. After the first few minutes, the video is about a series of primes.

I did set the video to begin at the correct spot, which it does @ 1min 51", sorry for any confusion. I don't understand the earlier examples that use complete sets but it was the randomness of the primes that I find perplexing.

 

[BWV]

Trivially, we have
$$0.a_1a_2a_3\ldots a_i=\sum_{i>0}{\frac{a_i}{10^i}}$$
Did you have something different in mind?

Yes, a nontrivial answer

 

[TeethWhitener]

Yes, a nontrivial answer

Put more effort into your question and people might put more effort into their responses. I don’t want to play a guessing game as to what you might mean here.

 

[PeroK]

Yes, a nontrivial answer

That's not a trivial solution. It's merely a simple, elegant solution. And as good as any other.

 

[sysprog]

I agree with @PeroK here $-$ in my view (which view is in my opinion less expert in the matter than is that of @PeroK or that of @TeethWhitener), the response of @TeethWhitener was spot-on $-$ it left the original question well-answered: he showed that a trivial solution was available, then brought in the fact that "the rationals are dense in the reals, meaning that any real number can be approximated arbitrarily accurately by the rationals", and also made sure to check lest his so-produced provisional 'yes' answer might not have addressed what the OP (@bland) was driving at.

 

[DrClaude]

The prime method in the video is to take all prime numbers ≥ 2 and take the product of 1 + 1/p if p-1 is divisible by 4 and 1 - 1/p, giving
$$
\left(1 - \frac{1}{3} \right) \left(1 + \frac{1}{5} \right) \left(1 - \frac{1}{7} \right) \left(1 - \frac{1}{11} \right) \left(1 + \frac{1}{13} \right) \left(1 + \frac{1}{17} \right) \left(1 - \frac{1}{19} \right) \cdots = \frac{2}{\pi}
$$
which I think can be written succinctly as
$$
\prod_{k=2}^{\infty} \left(1 + \frac{(-1)^{(p_k \mod 4 -1)/2}}{p_k} \right) = \frac{2}{\pi}
$$
where $p_k$ is the $k$th prime.

I am also very curious to know why this works.

I have tried calculating it in Mathematica, defining
$$
f_p(n) = 2 \left[ \prod_{k=2}^{n} \left(1 + \frac{(-1)^{(p_k \mod 4 -1)/2}}{p_k} \right) \right]^{-1}
$$
such that
$$
\lim_{n \rightarrow \infty} f_p(n) = \pi
$$
but the convergence is extremely slow. For instance, taking the first million primes gives
$$
f_p(1000000) \approx 3.141571749764497
$$

 

[jedishrfu]

There is no royal road to $\pi$ only one that slowly converges on it. :-)

 

[Hornbein]

Gosh, that's amazing. I know I'll never be able to figure it out.

 

[pbuk]

My point/joke was that you might break pi's decimal expansion into a concatenation of primes.

Have you ever tried? It gets surprisingly difficult surprisingly quickly.

 

[Vanadium 50]

No. I tried to see whether this was an issue with normal numbers and it got messy quickly.

 

[pbuk]

I had hoped this would give me a sumbission for OEIS but it's already A047777.

 

[sysprog]

I had hoped this would give me a sumbission for OEIS but it's already A047777.

I think that you might be interested in this, or might know someone who might be:

​ ​ ALCF GPU Hackathon: Applications Due May 24​ ​

​ ​ DATES July 19, July 26-28, 2022 ONLINE EVENT ​ The ALCF, in collaboration with NVIDIA, will host a free GPU hackathon on July 19 and July 26-28, 2022. The multi-day virtual event is designed to help teams of three to six developers accelerate their codes on ThetaGPU using a portable programming model, such as OpenMP, or an AI framework of their choice. Each team will be assigned mentors for the duration of the event to provide guidance on porting their code to GPUs or optimizing its performance. No previous GPU experience is required, but teams are expected to be fluent with the code they bring to the event and motivated to make progress at the hackathon. HPC, AI, or data science projects are welcome. Applications to participate are due May 24, 2022. For more details or to apply, visit: https://www.alcf.anl.gov/events/2022-alcf-gpu-hackathon ​ ​ If you have any questions, please contact us at training@alcf.anl.gov. ​ APPLY​ ​ ​ ​ ​ ​ Copyright © 2022 Argonne Leadership Computing Facility, All rights reserved.

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(post edited to include this link: https://www.alcf.anl.gov/support-center/theta/theta-thetagpu-overview)

 

[pbuk]

I think that you might be interested in this, or might know someone who might be:

Nah, not even 12 petaflops? Waste of electricity .

I'm not really interested in aspects of number theory that are only significant to ten-fingered humans anyway, I just fancied an entry in OEIS but now I see that this area is well covered already. It doesn't even make a good quiz question:

Q. What sequence is this:
14159,
2,
653,
5,
89,
7,
9323,
846264338327950288419716939937510582097494459230781640628620899862803482534211706798214808651328230664709384460955058223172535940812848111745028410270193852110555964462294895493038196442881097566593344612847564823378678316527120190914564856692346034861045432664821339360726024914127372458700660631558817488152092096282925409171536436789259036001133053054882046652138414695194151160943305727036575959195309218611738193261179310511854807446237996274956735188575272489122793818301194912983367336244065664308602139494639522473719070217986094370277053921717629317675238467481846766940513200056812714526356082778577134275778960917363717872146844090122495343014654958537105079227968925892354201995611212902196086403441815981362977477130996051870721134999999837297804995105973173281609631859502445945534690830264252230825334468503526193118817101000313783875288658753320838142061717766914730359825349042875546873115956286388235378759375195778185778053217122680661300192787661119590921642019893809525720106548586327886593615338182796823030195203530185296899577362259941389124972177528347913151557485724245415069595082953311686172785588907509838175463746493931925506040092770167113900984882401285836160356370766010471018194295559619894676783744944825537977472684710404753464620804668425906949129331367702898915210475216205696602405803815019351125338243003558764024749647326391419927260426992279678235478163600934172164121992458631503028618297455570674983850549458858692699569092721079750930295532116534498720275596023648066549911988183479775356636980742654252786255181841757467289097777279380008164706001614524919217321721477235014144197356854816136115735255213347574184946843852332390739414333454776241686251898356948556209921922218427255025425688767179049460165346680498862723279178608578438382796797668145410095388378636095068006422512520511739298489608412848862694560424196528502221066118630674427862203919494504712371378696095636437191728746776465757396241389086583264599581339047802759009946576407895126946839835259570982582262052248940772671947826848260147699090264013639443745530506820349625245174939965143142980919065925093722169646151570985838741059788595977297549893016175392846813826868386894277415599185592524595395943104997252468084598727364469584865383673622262609912460805124388439045124413654976278079771569143599770012961608944169486855584840635342207222582848864815845602850601684273945226746767889525213852254995466672782398645659611635488623057745649803559363456817432411251507606947945109659609402522887971089314566913686722874894056010150330861792868092087476091782493858900971490967598526136554978189312978482168299894872265880485756401427047755513237964145152374623436454285844479526586782105114135473573952311342716610213596953623144295248493718711014576540359027993440374200731057853906219838744780847848968332144571386875194350643021845319104848100537061468067491927819119793995206141966342875444064374512371819217999839101591956181467514269123974894090718649423196156794520809514655022523160388193014209376213785595663893778708303906979207,
73,
?