Is (S^n) X R Parallelizable for All n?

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Discussion Overview

The discussion revolves around the parallelizability of the product manifold (S^n) X R for all n, focusing on the mathematical properties and potential proofs related to this concept.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant seeks help to prove that (S^n) X R is parallelizable for all n.
  • Another participant requests clarification on the initial participant's progress and specific difficulties encountered.
  • A participant proposes to show that (S^n) X R is diffeomorphic to R^(n+1) \ {0}, suggesting that if R^(n+1) \ {0} is parallelizable, then (S^n) X R would also be parallelizable.
  • A later reply elaborates on the idea of R^(n+1) \ {0} being a subset of R^(n+1) and mentions the possibility of writing down a global trivialization for R^(n+1) that could restrict to a global frame for R^(n+1) \ {0}.
  • The same participant provides an example of a global frame for R^(n+1) as a list of standard basis vectors.

Areas of Agreement / Disagreement

The discussion does not present a consensus, as participants are exploring different approaches and have not yet resolved the question of parallelizability.

Contextual Notes

Participants have not fully established the necessary conditions or assumptions required to prove the parallelizability of R^(n+1) \ {0} or its implications for (S^n) X R.

amd939
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Hi, I am new to manifold and having a hard time on it. :frown: Could anyone please help me on the following problem. Please write down your thoughts. Thanks a lot.

Prove that (S^n) X R is parallelizable for all n.
 
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Show us what you've done so far and tell us precisely where you're stuck.
 
Hi,I tried to show S^nXR is parallelizable by showing S^nXR is diffeomorphic to R^n+1\{0} so if R^n+1\{0} is parallelizable then the problem solved. But I just don't know how to show R^n+1\{0} is parallelizable.
 
amd939 said:
Hi,I tried to show S^nXR is parallelizable by showing S^nXR is diffeomorphic to R^n+1\{0} so if R^n+1\{0} is parallelizable then the problem solved. But I just don't know how to show R^n+1\{0} is parallelizable.

R^(n+1)\{0} is a subset of R^(n+1). You can explicitly write down a global trivialization for R^(n+1) that restricts to a global frame for R^(n+1)\{0}.

A global frame for R^(n+1) is...

(1,0,...,0)
(0,1,0,...,0)
.
.
.
(0,...,0,1)
 

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