Is sin(h) equal to 1 when h = 1?

  • Context: Undergrad 
  • Thread starter Thread starter AdamS
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SUMMARY

The discussion clarifies that sin(h)/h equals 1 only as h approaches 0, not when h equals 1. When h is set to 1, the value of sin(1) is approximately 0.8414709848, leading to a result of 0.8414709848 when divided by 1. The confusion arises from misinterpreting the limit of sin(h)/h as h approaches zero, which is indeed equal to 1. A reference link is provided for further understanding of this limit concept.

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AdamS
I read that

sin(h)
------- = 1
h


If h = 1 then
my Calc shows that sin(1) = .8414709848
if we then divide that by 1

we get .8414709848

so how is it supposed to be 1?

I put my calc in Radian and Degree mode, neither give the result of 1.
 
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You have probably misread. It probably said "the limit of sin(h)/h as h tends to zero, is 1". Click http://people.hofstra.edu/faculty/Stefan_Waner/trig/triglim.html for a proof.
 
Last edited by a moderator:
if you read something and you not sure of what youi've read, try working with what youi've got: here you're saying that sin(h)=h which can't be true.l
 

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