Is SU(3) always contains SU(2) groups?

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SUMMARY

The discussion centers on the relationship between the special unitary groups SU(3), SU(2), and U(1). It is established that SU(3) contains non-trivial SU(2) subgroups, as evidenced by the existence of multiple SU(2) subgroups within SU(3). Additionally, the compatibility of SU(3) with the direct product SU(3) x SU(2) x U(1) is affirmed, as SU(2) is a subgroup of SU(3) and U(1) is a subgroup of SU(2). The inquiry also touches on the mathematical implications of subgroup inclusion and the concept of compatibility in group theory.

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  • Understanding of group theory, specifically the properties of special unitary groups.
  • Familiarity with the concepts of subgroup inclusion and direct products in algebra.
  • Knowledge of the mathematical notation and terminology related to SU(n) groups.
  • Basic grasp of tensor products and their implications in group theory.
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  • Research the properties and applications of SU(3) groups in particle physics.
  • Study the structure and significance of subgroup chains in group theory.
  • Explore the role of U(1) in the Standard Model of particle physics.
  • Learn about the mathematical framework of direct products and their relevance in theoretical physics.
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This discussion is beneficial for mathematicians, theoretical physicists, and students studying group theory, particularly those interested in the applications of SU(3), SU(2), and U(1) in particle physics and advanced algebra.

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Hi,

I trying to understand. If there is non-trivial SU(3) group, is it always possible to find SU(2) as part of SU(3)?
And same question about SU(2) and U(1).
 
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Sure, there are many ##SU(2)## subgroups of ##SU(3)## just like there are many ##O(2)## subgroups of ##O(3)##.
 
Thanks.

And another question about same.
SU(3) seems as have less number of parameters than SU(3)xSU(2)xU(1).
If there is SU(3) group, is is possible to say it is compatible with SU(3)xSU(2)xU(1) because SU(3) always contains SU(2) subgroups, and SU(2) always contains U(1)?
 
The group, ##G_1\times G_2## is the tensor product of two independent groups. ##G_1## is contained in ##G_1\times G_2## by the projection ##\pi : (g1,g2)\rightarrow g1##. The subgroup inclusion discussed in my previous reply is a subgroup of a different sort. (Mathematics is not my strongest subject) It would help to know what you mean by "compatible?"
 
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