Is Substitution x=1/t Correct for This Integral?

[pcvrx560]

If I had an integral

\int_{-1}^{1}e^{x}dx

Then performing the substitution x=\frac{1}{t} would give me

\int_{-1}^{1}-e^\frac{1}{t}t^{-2}dt

Which can't be right because the number in the integral is always negative. Is this substitution not correct?

Sorry if I am being very thick but I can't figure out why I can't evaluate this simple integral with this change of variables.

 

[tiny-tim]

hi pcvrx560!

… Is this substitution not correct?

the substitution is fine, but the limits are wrong …

as x goes up from -1 to 1,

t (= 1/x) goes down from -1 to -∞, and then from +∞ down to 1 …

you'ld need to write $\int_{-1}^{-\infty} + \int_{\infty}^{1}$

(or $-\int^{-1}_{-\infty} - \int^{\infty}_{1}$)​

 

[SteamKing]

Isn't the integral of e^x w.r.t. x simply e^x + C?

 

[pcvrx560]

Thanks, tiny-tim! That cleared it up for me.

I didn't think about the range I was integrating over, I was just mindlessly plugging numbers into 1/t.