Is Tan(x) Locally Lipschitz?

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gaganaut
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Would a trig function like [tex]tan \left(x\right)[/tex] be locally Lipschitz?

How do we know that, if we know that [tex]tan \left(x\right)[/tex] is not continuously differentiable?
 
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tan(x) is continuously differentiable everywhere where it is defined.

And following my geometrical intuition, I would say that it is locally lip****z, and that you would have to try hard to find a function that is continuous but not locally lipschitz!
 
quasar987 said:
And following my geometrical intuition, I would say (...) you would have to try hard to find a function that is continuous but not locally lipschitz!
Not that hard though, e.g.
[tex][-1,1]\to\mathbb{R}[/tex]
[tex]x\mapsto x^{1/3}[/tex]
is not Lipschitz on any nhbd of zero.