Is the Calculation of Torque to Lift 100kg Accurate?

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    F=ma Lift Torque
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Discussion Overview

The discussion centers around the calculation of torque required to lift a 100kg mass, with participants examining the accuracy of the initial calculations provided by the original poster. The scope includes technical reasoning and clarification of concepts related to torque and force.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • The original poster calculates the force as F=100x9.81, resulting in F=981N, and subsequently calculates torque as T=981x0.77, yielding T=755Nm.
  • One participant expresses uncertainty about the calculations and requests clarification on the device's operation.
  • Another participant suggests that the angle should be considered in the torque calculation, referencing the formula Torque = Fdsin(x), but admits uncertainty about its application.
  • A different participant provides a link to an external resource that may contain relevant calculations for torque required to move a mass uphill.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the accuracy of the original torque calculation, with some questioning its validity and others suggesting additional factors to consider.

Contextual Notes

There is a lack of clarity regarding the drawing referenced by the original poster, and the assumptions regarding the angle in the torque calculation remain unresolved.

geek743
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Hi all,
Please note this is not a home work.
Working on a NPD.Please look at the jpeg file

I have done few basic calculations to find torque to lift 100kg
F=Ma
F=100x9.81
F=981N

Torque=Force x Distance
T=981x.77
T=755Nm

The torque on the gearbox output shaft required to lift is 755Nm

Is this calculation correct?

Any help on this is much appreciated

Regards
Geek743
 

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Hi
Is this question still open? I do not really understand your drawing but i think there is a problem with your calculations. Please explain how should work your device.
 


I think you need to provide more info with your drawing and how it works. remember Torque = Fdsin(x) I believe you need to consider the angle as well, but I'm not entirely sure how this works either
 

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