Is the Calorimeter Constant Calculation Correct?

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The discussion focuses on the calculation of the calorimeter constant using the heat exchange between hot and cold water. The heat lost by hot water is calculated as -4942.85 J, while the heat gained by cold water is 3619.88 J. The heat gained by the calorimeter is determined to be 1322.97 J. The final calorimeter constant is derived as 76.38. The accuracy of the last calculation is questioned, but it appears to be correct based on the provided values.
blicker
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Homework Statement


cold water: 50g
cold water temp: 22.23 C
hot water: 50 g
hot water temp: 63.2 C
final temp: 39.55 C


Homework Equations





The Attempt at a Solution


heat lost by hot water:
(4.18)(50)(39.55-63.22)=-4942.85

heat gained by cold water:
(4.18)(50)(39.55-22.23)=3619.88

heat gained by calorimeter:
-(-4942.85 J+3619.88 J)=1322.97 J

calorimeter constant:
1322.97/17.32=76.38

is this right? I am especially not sure about the last one.
 
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Looks OK to me.
 

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