# How do I calculate heat lost by the hot water in a calorimeter?

• blicker
In summary, the task at hand is to calculate the heat lost by the hot water in a calorimeter using the given information of initial and final temperature, density, and specific heat capacity. The two equations provided, q=mCΔT and qmetal=-(qwater+qmetal), are both applicable for solving this problem. However, with only the density given, it is not enough information to use the first equation. The student also has a separate question about calculating the heat gained by the water in the calorimeter after adding aluminum, but without knowing the procedure followed, it is difficult to provide an answer.
blicker

## Homework Statement

1. Calculate heat lost by the hot water in the calorimeter.
Initial temp: 22.90 C
Finial temp: 23.25 C
Density: 1.00 g/mL
specific heat capacity: 4.18 J/gK

## Homework Equations

qmetal=-(qwater+qmetal)

q=m C dT

## The Attempt at a Solution

When i use the second equation i end up stuck.
=(mass of water)(4.18)(23.25-22.90)

but he didnt give us a mass he gave us density. So i think I am supposed to use the first eqauation, but i don't know where to start with that one. how would i solve this problem with the first equation? Or are the two equations basically the same thing?

Just density is not enough.

Is it all information you were given?

yes that's all he gave us. ill have to ask him about that question.
another question i have is how to calculate the heat gained by the water in the calorimeter after adding the aluminum.

this is what he gave us:
temp of water in calorimeter before adding metal: 22.90 C
mass of test tube: 32.679 g
mass of aluminum: 50.155 g
temp of aluminum: 100 C
temp of aluminum and water 32.19 C
temp of water in calorimeter after adding metal: 23.25 C

blicker said:
temp of water in calorimeter before adding metal: 22.90 C
mass of test tube: 32.679 g
mass of aluminum: 50.155 g
temp of aluminum: 100 C
temp of aluminum and water 32.19 C
temp of water in calorimeter after adding metal: 23.25 C

Not knowing procedure that was followed I have no idea what is what of what.

Perhaps this is a series of questions and they are somehow related - that is, answer from earlier question can be used as input in the next one?

no this is a separte question from the first one i asked.

## 1. What is heat capacity?

Heat capacity is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius.

## 2. How is heat capacity measured?

Heat capacity is measured by the ratio of the amount of heat energy absorbed by a substance to the corresponding change in temperature.

## 3. What factors affect heat capacity?

The heat capacity of a substance is affected by its mass, composition, and phase (solid, liquid, or gas).

## 4. How does heat capacity relate to heat lost?

The heat capacity of a substance determines how much heat energy it can absorb or lose. The amount of heat lost by a substance is directly proportional to its heat capacity.

## 5. How is heat capacity used in practical applications?

Heat capacity is important in designing heating and cooling systems, as well as in calculating the amount of energy needed to heat or cool a substance. It is also used in thermodynamics and in determining the specific heat of materials.

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