How do I calculate heat lost by the hot water in a calorimeter?

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Discussion Overview

The discussion revolves around calculating the heat lost by hot water in a calorimeter, specifically focusing on the parameters provided, such as initial and final temperatures, density, and specific heat capacity. The context includes homework-related queries and the application of thermodynamic equations.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant presents a homework problem involving the calculation of heat lost by hot water, using the equation q = m C dT, but expresses confusion about the mass of water since only density is provided.
  • Another participant questions whether the information given is sufficient to solve the problem, indicating that density alone may not be enough.
  • A participant mentions needing to ask the instructor for clarification regarding the mass of water and raises a related question about calculating heat gained by water after adding aluminum.
  • Further details about the experimental setup are provided, including temperatures and masses of the aluminum and test tube, but one participant expresses uncertainty about the procedure followed.
  • One participant clarifies that the second question regarding heat gained by water is separate from the first question about heat lost.

Areas of Agreement / Disagreement

Participants do not reach a consensus on how to proceed with the calculations due to insufficient information regarding the mass of water. Multiple views on the adequacy of the provided data exist, and the discussion remains unresolved.

Contextual Notes

Limitations include the lack of mass for the water, which is necessary for calculations, and the dependence on the specific procedure followed in the experiment, which is not detailed in the posts.

blicker
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Homework Statement


1. Calculate heat lost by the hot water in the calorimeter.
Initial temp: 22.90 C
Finial temp: 23.25 C
Density: 1.00 g/mL
specific heat capacity: 4.18 J/gK

Homework Equations


qmetal=-(qwater+qmetal)

q=m C dT

The Attempt at a Solution


When i use the second equation i end up stuck.
=(mass of water)(4.18)(23.25-22.90)

but he didnt give us a mass he gave us density. So i think I am supposed to use the first eqauation, but i don't know where to start with that one. how would i solve this problem with the first equation? Or are the two equations basically the same thing?
 
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Just density is not enough.

Is it all information you were given?
 
yes that's all he gave us. ill have to ask him about that question.
another question i have is how to calculate the heat gained by the water in the calorimeter after adding the aluminum.

this is what he gave us:
temp of water in calorimeter before adding metal: 22.90 C
mass of test tube: 32.679 g
mass of aluminum: 50.155 g
temp of aluminum: 100 C
temp of aluminum and water 32.19 C
temp of water in calorimeter after adding metal: 23.25 C
 
blicker said:
temp of water in calorimeter before adding metal: 22.90 C
mass of test tube: 32.679 g
mass of aluminum: 50.155 g
temp of aluminum: 100 C
temp of aluminum and water 32.19 C
temp of water in calorimeter after adding metal: 23.25 C

Not knowing procedure that was followed I have no idea what is what of what.

Perhaps this is a series of questions and they are somehow related - that is, answer from earlier question can be used as input in the next one?
 
no this is a separte question from the first one i asked.
 

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