Is the Calorimeter Constant Calculation Correct?

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SUMMARY

The calorimeter constant calculation presented in the discussion is based on the heat transfer between cold and hot water. The heat lost by hot water is calculated as -4942.85 J, while the heat gained by cold water is 3619.88 J. The heat gained by the calorimeter is determined to be 1322.97 J, leading to a calorimeter constant of 76.38 J/°C. This calculation is confirmed as correct by participants in the discussion.

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  • Understanding of specific heat capacity (4.18 J/g°C)
  • Basic knowledge of heat transfer principles
  • Familiarity with calorimetry concepts
  • Ability to perform algebraic calculations involving temperature changes
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blicker
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Homework Statement


cold water: 50g
cold water temp: 22.23 C
hot water: 50 g
hot water temp: 63.2 C
final temp: 39.55 C


Homework Equations





The Attempt at a Solution


heat lost by hot water:
(4.18)(50)(39.55-63.22)=-4942.85

heat gained by cold water:
(4.18)(50)(39.55-22.23)=3619.88

heat gained by calorimeter:
-(-4942.85 J+3619.88 J)=1322.97 J

calorimeter constant:
1322.97/17.32=76.38

is this right? I am especially not sure about the last one.
 
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Looks OK to me.
 

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