Is the concept of "wave function collapse" obsolete?
- Context: Graduate
- Thread starter Sophrosyne
- Start date
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
137 replies · 26K views
Physics news on Phys.org
- 24,488
- 15,063
The solution of the Schrödinger equation allows it very well. It tells you that I simply have to pick a silver atom from one of the partial beams prepared by running the silver atoms through the magnetic field. Due to the position-spin-component-entanglement I've a silver atom in a pure ##S_z=1/2## state.A. Neumaier said:Nothing in quantum theory without collapse allows you to conclude this!
- 24,488
- 15,063
Just tell me, where in the argument that I simply have to select a silver atom from one of the partial beams prepared by running the silver atoms through the magnetic field to have silver atom prepared in a pure ##S_z=1/2## state I need a the collapse postulate. Nowhere is instantanteous actions at a distance, just the quite local choice, which silver atom to work with after it has run through a magnetic field.DarMM said:Well I'm not arguing for determinism or that QM is wrong, I'm just flummoxed as to how one removes the collapse postulate.
Michael Price
- 344
- 94
There are three independent proofs of Born.DarMM said:It's not. Even MWI people today don't believe Everett's derivation is valid. Literally his analysis isn't mathematically valid. See the lectures of Matt Leifer where he discusses this. I've done a long analysis of the proofs of Born's rule in MWI in another thread. I'll discuss this in another thread.
1) Everett's Gleason-style proof.
2) Dewitt's frequentist proof (in Physics and Reality)
3) Zurek's symmetry based proof.
Science Advisor
Gold Member
- 2,369
- 1,408
I'm not talking about instantaneous action at a distance. I'm just talking about the collapse postulate.vanhees71 said:Nowhere is instantanteous actions at a distance, just the quite local choice, which silver atom to work with after it has run through a magnetic field
QM will not tell you which beam a given atom will be in. So the formalism will just say it has a 50% chance to be in one beam, 50% chance to be in the other. Then when you find it to be in a given beam or take an atom from one beam you can then ignore the "50%" term related to the other beam.vanhees71 said:Just tell me, where in the argument that I simply have to select a silver atom from one of the partial beams prepared by running the silver atoms through the magnetic field to have silver atom prepared in a pure ##S_z=1/2## state I need a the collapse postulate.
Collapse is just a generalisation of conditioning in probability. That's why I don't get this, it even occurs in basic probability theory with conditional updating of probabilities.
- 24,488
- 15,063
I think that's a debate about what you call a "derivation of Born's rule", i.e., which assumptions you are accepting as "sufficiently independent" of Born's rule. I think, from a physics point of view, it doesn't make much difference, whether you can derive Born's rule from some other assumptions. A good thing of such proofs might be to understand certain aspects of QT better, but I think after all we have to accept it as a property of nature, as we have to accept that electromagnetic waves are described by Maxwell's equations or the standard model by local gauge symmetries. It's just a result of many careful investigations of nature in terms of observations/experiments and mathematical analysis towards their systematic quantitative description.
Science Advisor
Gold Member
- 2,369
- 1,408
There is also the Oxford Decision theoretic derivation and Vaidman and Carroll's self-locating derivation. I know all of them. As I said I've discussed them in other threads.Michael Price said:There are three independent proofs of Born.
1) Everett's Gleason-style proof.
2) Dewitt's frequentist proof (in Physics and Reality)
3) Zurek's symmetry based proof.
Michael Price
- 344
- 94
Oxford/Deutsch is just too complex, and Carroll's is basically Zurek (but more complex). People that don't get these derivations fall into two camps.DarMM said:There is also the Oxford Decision theoretic derivation and Vaidman and Carroll's self-locating derivation. I know all of them. As I said I've discussed them in other threads.
1) those infected by philosophy
2) those that recoil from MWI.
Science Advisor
Gold Member
- 2,369
- 1,408
Carroll and Zurek have quite different assumptions, i.e. quite different postulates about the quantum states of subsystems have to be true. They're not the basically the same.Michael Price said:Oxford/Deutsch is just too complex, and Carroll's is basically Zurek (but more complex). People that don't get these derivations fall into two camps.
1) those infected by philosophy
2) those that recoil from MWI.
I'm not sure what you mean by the last part.
- 24,488
- 15,063
Of course, QM will not tell me which beam a given atom will be in. But that's not a problem, because indeed as you say, I can just decide to use the 50% of the atoms I want to have (with determined spin component).DarMM said:QM will not tell you which beam a given atom will be in. So the formalism will just say it has a 50% chance to be in one beam, 50% chance to be in the other. Then when you find it to be in a given beam or take an atom from one beam you can then ignore the "50%" term related to the other beam.
Collapse is just a generalisation of conditioning in probability. That's why I don't get this, it even occurs in basic probability theory with conditional updating of probabilities.
That's the point: You don't need the collapse. It's just precisely what you say, the "conditional updating of probabilities". Nowhere is something needed that (a) outside of quantum dynamical laws (in other words, you don't need a "Heisenberg cut") nor do I need (b) spooky actions at a distance (which follows from (a), because in relativistic QFTs you envoke the microcausality constraint in building your models to begin with).
In our example, I just select 50% of the "right atoms" and through the other 50% of the "bad atoms" away and then precisely know the probabilities for the "right atoms". The selection is just guaranteed by blocking out the "bad atoms", which is a local interaction of them with a piece of matter, following the dynamics of local interactions of relativistic QFT.
Science Advisor
Gold Member
- 2,369
- 1,408
That's what "collapse" refers to in the basic formalism. Conditioning the state upon observations. So when you say you reject collapse, you mean you reject thinking of updating the quantum state in terms of some instantaneous physical process. That's fine, but it's very confusing as that's not what "collapse" refers to.vanhees71 said:That's the point: You don't need the collapse. It's just precisely what you say, the "conditional updating of probabilities"
- 24,488
- 15,063
Well, then you have a different understanding of the word "collapse" than I have. Of course, I don't deny the "collapse" in this sense. To apply probability theory to the real world (aka statistics) that's what you have to do. In this sense also the outcome of the Saturday's drawing of the lotery numbers in Germany is a "collapse".
The problem is that collapse in the context of QT usually means that
(a) it's according to some (unspecific) classical dynamical laws outside of the QT formalism. The claim is that such a "Heisenberg cut" is necessary.
(b) it's working non-locally, i.e., the collapse violates Einstein causality.
I think (a) is unncessary and also not justified by observations. There's no evidence for the invalidity of QT but a quite well understood explanation for the fact that macroscopic systems usually behave according to classical physics concerning the "relevant macroscopic observables". (b) is simply wrong, because it contradicts the very fundamental construction of relativistic QT in terms of microcausal (aka local) QFT.
The problem is that collapse in the context of QT usually means that
(a) it's according to some (unspecific) classical dynamical laws outside of the QT formalism. The claim is that such a "Heisenberg cut" is necessary.
(b) it's working non-locally, i.e., the collapse violates Einstein causality.
I think (a) is unncessary and also not justified by observations. There's no evidence for the invalidity of QT but a quite well understood explanation for the fact that macroscopic systems usually behave according to classical physics concerning the "relevant macroscopic observables". (b) is simply wrong, because it contradicts the very fundamental construction of relativistic QT in terms of microcausal (aka local) QFT.
Science Advisor
Gold Member
- 2,369
- 1,408
Yes indeed. Then we just have different terminology.vanhees71 said:In this sense also the outcome of the Saturday's drawing of the lotery numbers in Germany is a "collapse"
The only thing I'll say is that the "cut" isn't really about collapse needing classical laws. It's a separate thing, but not suited to this thread.
Science Advisor
Gold Member
- 1,114
- 1,015
vanhees71 said:Of course, QM will not tell me which beam a given atom will be in. But that's not a problem, because indeed as you say, I can just decide to use the 50% of the atoms I want to have (with determined spin component).
That's the point: You don't need the collapse.
What the heck do you want to tell?
When you partially block the beam in a say z-oriented Stern-Gerlach apparatus which is fed with a beam of say |+x> polarized particles, you simply acquire a “which path information”. That’s at the end a measurement leading to a “state reduction” to say |+z> or |-z>. There exist no subensembles in the Stern-Gerlach apparatus. As long as nothing is blocked, every particle is in its |+x> state.
- 24,488
- 15,063
I know which beam to block to get the one I want. I simply put a piece of matter in the way of the other beam.
If you have a ##|+x \rangle## polarized particle and let it run through a SG-magnetic field in ##z## direction, it's state is involving in a state where the spin-z component is entangled with the position of the particle, and thus I know, whether the particle has ##\sigma_z=1/2## or ##\sigma_z=-1/2##. I just need to check, where it is located.
Of course running through the magnetic field, now ##\sigma_x## got maximally randomized again, no matter whether or not I block particles or not.
If you have a ##|+x \rangle## polarized particle and let it run through a SG-magnetic field in ##z## direction, it's state is involving in a state where the spin-z component is entangled with the position of the particle, and thus I know, whether the particle has ##\sigma_z=1/2## or ##\sigma_z=-1/2##. I just need to check, where it is located.
Of course running through the magnetic field, now ##\sigma_x## got maximally randomized again, no matter whether or not I block particles or not.
Science Advisor
Gold Member
- 1,114
- 1,015
vanhees71 said:Of course running through the magnetic field, now σx\sigma_x got maximally randomized again, no matter whether or not I block particles or not.
In case you would recombine "both beams", you would find every particle in the pure |+x> state again. Nothing is randomnized.
Mentor
- 50,515
- 26,563
Thread closed for moderation.
- 20,819
- 28,466
It seems the discussion came to a kind of end. As we already have many threads with this topic or similar, this one will remain closed.
Similar threads
Graduate Wave Function Collapse and Thermodynamic Irreversible Processes
- hyksos
- · Replies 4 ·
- Quantum Physics
- Replies
- 4
Graduate Wave Function Collapse: Observers & Probability in Schrodinger's Cat Experiment
- leonstavros
- · Replies 4 ·
- Quantum Physics
- Replies
- 4
Graduate Description of Wave Function Collapse
- Couchyam
- · Replies 7 ·
- Quantum Physics
- Replies
- 7