Is the degeneracy of N2+ different from N2?

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The degeneracy of the diatomic molecules N2 and its ion N2+ can be calculated using specific statistical weights. For N2 in the C3∏u state, the degeneracy is determined to be 6, while for N2+ in the B2Σg+ state, it is 2. The calculation involves considering electron spin, vibrational, and rotational statistical weights, with the rotational weight dependent on the nuclear spin states. The differences in allowed rotational states due to the symmetry of the molecular states (u vs. g) do not significantly affect the overall degeneracy values.

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The calculation of degeneracy of diatomic molecules can be easily found. However, there is no detail introduction of ions. Not sure if the electronic, vibrational, rotational, and nuclear spin statistical weights are differ from N2+ to N2. Please help. Thanks.
 
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Can you clarify what you mean by degeneracy (degeneracy of what)?
 
DrClaude said:
Can you clarify what you mean by degeneracy (degeneracy of what)?
I am trying to calculate the electron temperature using optical emission spectrum intensity ratio. The equation includes degeneracy values of N2(C3πu) and N2+(B2Σg+). I have found the way to get the degeneracy of N2(C), but not sure if I can do the same thing to the excited ion N2+(B).
 
Well, one is a doublet and the other a triplet, so that will have to be taken into account. Also, concerning rotation, you have to consider that one is u and the other g, so that will change which rotational states are allowed, but at first glance I don't see why this should affect the degeneracy.
 
DrClaude said:
Well, one is a doublet and the other a triplet, so that will have to be taken into account. Also, concerning rotation, you have to consider that one is u and the other g, so that will change which rotational states are allowed, but at first glance I don't see why this should affect the degeneracy.
Thanks for the reply.

My trouble is to find the degeneracy of N2(C3u) and the degeneracy of N2+(B2Σg+). So far, according to the literature [1], the degeneracy is a product of electron spin statistical weight, vibrational statistical weight, and rotational statistical weight. According to [2], the one of electron spin equals to 2S+1 for Σ states and 2(2S+1) for other states. Thus for N2(C), the value is 6, and for N2+(B), it is 2. Literature [2] also suggests the vibrational degeneracy is unity. However, for the rotational one, grot=(2J+1)gsgi, where gs and gi are "state dependent" and "state independent" weights determined by nuclear spin. My spectrum comes from electron impact excitation in a plasma, rather than light scattering on a target. Therefore, I have no idea how to get J value without rotational Raman spectrum. Also, for N2+(B) which is a Bose system at s level, its gs = 6, but I have no idea how to find gs for N2(C) since it is same for symmetric and antisymmetric rotational level.

[1] M. Simeckova et al, Einstein A-coefficients and statistical weights for molecular absorption transitions in the HITRAN database, J. Quant. Spectrosc. Ra., 98(2006) 130-155.
[2] J. B. Tatum, The interpretation of intensities in diatomic molecular spectra, Astrophys. J. Suppl., 14(1967) p.21.
 

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