Is the Derivative of (x^2-6x+9)(2x^2-x+1) Correct?

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SUMMARY

The derivative of the function (x^2-6x+9)(2x^2-x+1) is confirmed to be 8x^3 - 39x^2 + 50x - 15. The initial calculation included a miscalculation in the distribution of terms, particularly with the "4x" times "9" term. The correct application of the product rule and simplification leads to the final result, ensuring accuracy in polynomial differentiation.

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I need to find the derivative of:

(x^2-6x+9)(2x^2-x+1)

what i did:
(2x-6)(2x^2-x+1)+(4x-1)(x^2-6x+9)
4x^3-2x^2+2x-12x^2+6x-6+4x^3-24x^2-36x-x^2+6x-9
8x^3-39x^2-28x-15

is this correct?
 
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Take a closer look at that "4x" times "9" term again!
 
(2x-6)(2x^2-x+1)+(4x-1)(x^2-6x+9)
4x^3-2x^2+2x-12x^2+6x-6+4x^3-24x^2+36x-x^2+6x-9
8x^3-39x^2-50x-15

thanks, is this right?
 
I mean to write:
8x^3-39x^2+50x-15
 
that's what I got
 

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