Is the Dirac free equation actually free

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Discussion Overview

The discussion centers on the interpretation of the Dirac free equation, particularly regarding the implications of a "free" particle in quantum mechanics and the relationship between momentum, energy, and forces. Participants explore the theoretical and conceptual aspects of free particles, relativistic effects, and the complexities introduced by interactions with other particles.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Exploratory
  • Technical explanation

Main Points Raised

  • Some participants question whether a truly free particle should only possess rest energy, suggesting that the Dirac equation implies it can have any momentum.
  • Others argue that a free particle can have both rest energy and relativistic kinetic energy, indicating that momentum is not necessarily zero.
  • It is noted that "free" means not subject to forces, but this does not imply that momentum or kinetic energy must be zero.
  • Some contributions highlight that momentum and speed are relative to a frame of reference, which is necessary for describing physical states, including the vacuum state.
  • Participants discuss the implications of quantum mechanics, suggesting that particles are always influenced by forces, complicating the notion of being "free." Some assert that this leads to ambiguities in applying classical laws, such as Newton's first law, to quantum particles.
  • There are mentions of the Klein paradox and the challenges in interpreting the Dirac equation, with some suggesting that simplifications may lead to confusion in understanding particle behavior.
  • One participant proposes that the existence of another identical particle could affect the dispersion relation, hinting at the complexities involved in quantum field theory (QFT) and renormalization.
  • Concerns are raised about the frame-dependence of momentum and kinetic energy, with a suggestion that realistic conditions involving interactions with other particles could yield more accurate results.

Areas of Agreement / Disagreement

Participants express differing views on the implications of the Dirac free equation, with no consensus reached on the interpretation of "free" particles and the role of forces in quantum mechanics. Multiple competing perspectives remain on how to reconcile classical and quantum descriptions of particle behavior.

Contextual Notes

Discussions touch upon the limitations of classical mechanics in quantum contexts, the dependence of physical quantities on reference frames, and the challenges posed by interactions in quantum systems. These factors contribute to the ongoing debate regarding the interpretation of the Dirac equation.

ftr
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I mean the equation shows the particle could have any momentum, how did that came about. If it is truly free it should have only an energy of mc^2, shouldn't it.
 
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ftr said:
I mean the equation shows the particle could have any momentum, how did that came about. If it is truly free it should have only an energy of mc^2, shouldn't it.
No; this is only the rest energy. You also need to count the (relativistic) kinetic energy! A free nonrelativistic particle can also move with any momentum and then has an energy of ##p^2/2m##.
 
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"Free" means not subject to any forces, so the momentum is not changing. It does not follow that the momentum and hence the kinetic energywill be zero.
 
A. Neumaier said:
No; this is only the rest energy. You also need to count the (relativistic) kinetic energy! A free nonrelativistic particle can also move with any momentum and then has an energy of ##p^2/2m##.

In both cases the momentum or speed should be against/relative to something else, but that cannot happen for "single" particle, correct or not.
 
ftr said:
In both cases the momentum or speed should be against/relative to something else, but that cannot happen for "single" particle, correct or not.
It is against a fixed Lorentz frame in space-time. The frame is not a material entity but a way to describe space-time independent of its contents. It is needed even to describe the vacuum state - without it there is no meaning to the standard requirement that the vacuum state should be Lorentz invariant.
 
Nugatory said:
"Free" means not subject to any forces, so the momentum is not changing. It does not follow that the momentum and hence the kinetic energywill be zero.
At fundamental quantum level particles are subject to the "four" known forces, and these are relentless. Any particle subjected to them they will be under the influence no matter how small, but if they become so small then you are back to only mc^2. It seems that Newton's first law is ambiguous for quantum particles.
 
ftr said:
At fundamental quantum level particles are subject to the "four" known forces
A single electron alone in the universe will be free. Note that free particles are (like almost everything in physics) an abstraction form the all-too-complex reality. One simplifies and abstracts in order to be able to understand and classify.
 
A. Neumaier said:
A single electron alone in the universe will be free. Note that free particles are (like almost everything in physics) an abstraction form the all-too-complex reality. One simplifies and abstracts in order to be able to understand and classify.

Of course I understand that, I have a Master's in EE. But from following up on materials that spawned from recent threads by demystifier and Morgan it seems to me that simplification has led to confusion including the Klein paradox , a no solution relativistic particle in a box(or simple potentials) and ... so on with all of that carried to QFT as discussed in the mentioned threads. It just seems to me the interpretation or the "simplification" of original Dirac equation is the culprit.
 
To add: it seems to me to have that momentum realistically another identical particle has to exist and in that case the interaction might change the form of the dispersion relation. But I guess that will put us in QFT renormalization ..
 
  • #10
ftr said:
Any particle subjected to them they will be under the influence no matter how small, but if they become so small then you are back to only mc^2.
That is simply not true, because both the momentum ##p## and the kinetic energy ##p^2/2m## are frame-dependent - you can make them take on any value you please simply by choosing coordinates that make them come out the way you want no matter what forces are present or not.
It seems that Newton's first law is ambiguous for quantum particles.
It would be better to say that it doesn't apply - it's a classical description that assumes that both position and momentum can be known simultaneously.
 
  • #11
ftr said:
I mean the equation shows the particle could have any momentum, how did that came about. If it is truly free it should have only an energy of mc^2, shouldn't it.
What does the first Newton law say?
 
  • #12
Nugatory said:
momentum ppp and the kinetic energy p2/2mp2/2mp^2/2m are frame-dependent

That was my concern in the OP. That is why I said under realistic condition of interacting with another particle/s can give more realistic results.
 
  • #13
Demystifier said:
What does the first Newton law say?

In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force.

In QM settings it is usually particles interacting via potential or some scattering that are interesting and revealing/useful. Add to that particle trajectory issues and the UP.
 
  • #14

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