Is the Frictional Force on a Sloped Block Greater Than Its Weight?

[1Deag4Days]

Homework Statement

A block is at rest on a rough incline .
The frictional force acting on the block, along the incline, is
A) greater than the weight of the block.
B) equal to the weight of the block.
C) zero.
D) less than the weight of the block.

Homework Equations

The Attempt at a Solution

The frictional force should be equal to the Weight along the slope so MG/sin(theta) so shouldn't the frictional force be greater than the weight of the block?

 

[Nathanael]

The weight along the slope is greater than the total weight?

How do you get MG/sin(theta)? That would imply, as the angle theta goes to zero, the weight along the slope goes to infinity. Is that reasonable?

 

[1Deag4Days]

I know I'm doing something wrong but i don't know what

 

[1Deag4Days]

Nvm I got it I was decomposing my gravitational force vector incorrectly