Is the Frictional Force on a Sloped Block Greater Than Its Weight?

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Homework Help Overview

The problem involves a block at rest on a rough incline, focusing on the relationship between the frictional force acting on the block and its weight. Participants are exploring the dynamics of forces on an inclined plane.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of the frictional force in relation to the weight of the block, questioning whether it can be greater, equal, or less than the weight. There is also an inquiry into the derivation of the expression MG/sin(theta) and its implications as the angle approaches zero.

Discussion Status

The discussion reflects a mix of confusion and clarification, with one participant acknowledging a mistake in their approach to decomposing the gravitational force vector. Others are questioning the assumptions made regarding the forces involved.

Contextual Notes

Participants are grappling with the implications of the angle of the incline and how it affects the forces acting on the block, indicating a need for clearer definitions and understanding of the components of weight on an incline.

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Homework Statement


A block is at rest on a rough incline .
The frictional force acting on the block, along the incline, is
A) greater than the weight of the block.
B) equal to the weight of the block.
C) zero.
D) less than the weight of the block.

Homework Equations

The Attempt at a Solution



The frictional force should be equal to the Weight along the slope so MG/sin(theta) so shouldn't the frictional force be greater than the weight of the block?
 
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The weight along the slope is greater than the total weight?

How do you get MG/sin(theta)? That would imply, as the angle theta goes to zero, the weight along the slope goes to infinity. Is that reasonable?
 
I know I'm doing something wrong but i don't know what
 

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Nvm I got it I was decomposing my gravitational force vector incorrectly
 

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