Is the Infinite Sqrt Series Finite?

  • Context: Graduate 
  • Thread starter Thread starter PEZenfuego
  • Start date Start date
  • Tags Tags
    Infinite Series
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 3K views
PEZenfuego
Messages
48
Reaction score
0
I heard something interesting today, but I am skeptical. I heard that a certain infinite series has a finite answer and I was curious as to whether or not this was true and if we can prove it either way.

This is the series:

[tex]\sqrt{1+\sqrt{2+\sqrt{3+\sqrt{4+\sqrt{5...}}}}}[/tex]

Any thoughts would be very much appreciated.
 
Physics news on Phys.org
Taken from Wolfram Mathworld:

Wolfram Mathworld said:
Herschfeld (1935) proved that a nested radical of real nonnegative terms converges iff [tex]x_n^{2^{-n}}[/tex] is bounded.

So, the question is, is xn^(2^(-n)) bounded? To answer this, we realize that the nth term of x is simply n, and so we check the function...

[tex]f(n)=n^{2^{-n}}[/tex]

And we find that indeed, this function is bounded. So yes, your nested radical is convergent.
 
[tex]\sqrt{1+\sqrt{2+\sqrt{3+\sqrt{4+\sqrt{5...}}}}}\approx 1.7579327566180045327[/tex]