MHB Is the Irreducible Polynomial of u the Minimal Polynomial?

[Math Amateur]

I am studying field theory.

A general question I have is the following:

Let E \supseteq F be fields and let u \in E.

Now, if I determine an irreducible polynomial f in F[x] such that f(u) = 0 in E, can I conclude that I have found the minimal polynomial of u over F.

Can someone please help?

Peter

[Note: This has also been posted on MHF]

 

[Deveno]

Recall that in a UFD, irreducibles are only unique "up to a unit factor" (and the units of a polynomial ring over a field are the non-zero field elements), so to conclude $f$ is THE minimal polynomial of $u$, we must have that $f$ is MONIC. For example:

$f(x) = 3x^2 - 6$ is A(n irreducible) polynomial in $\Bbb Q[x]$ for which we have $f(\sqrt{2}) = 0$, but it is not THE minimal polynomial of $\sqrt{2}$ precisely because it is not monic. To fix this, we have to multiply by the unit $\frac{1}{3}$.

Also, as a practical matter, determining that $f(u) = 0$ is usually the easy part. Proving irreducibility is often much more difficult, especially with polynomials of degree 4 or higher, which is why they are not often used as examples.