Is the Mandelbrot Set Lebesgue Measurable?

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Dragonfall
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What is the Lebesgue measure of the Mandelbrot set?
 
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According to Wikipedia, the measure is estimated to be 1.506 591 77 ± 0.000 000 08, and it is conjectured to be exactly [tex]\sqrt{6\pi-1} - e[/tex]

edit: But after reading the source... I'm really not sure if I would trust that too well. However, the two large areas of the Mandelbrot set each definitely have positive measures
 
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How do you know that it's not Lebesgue measurable?
 
HallsofIvy said:
The mandelbrot set is not "Lebesque measurable". Is is possible that you are referring to the dimension of the set?

<< insult deleted by Mentors >> every closed set is Lebesgue measurable.

The Mandelbrot Set is closed.

J
 
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Dragonfall said:
How do you know that it's not Lebesgue measurable?

I know this is a very old post, but read what I just posted in reply.

J
 

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