Is the Nested Interval Theorem Flawed in My Textbook?

  • Context: Graduate 
  • Thread starter Thread starter pyfgcr
  • Start date Start date
  • Tags Tags
    Interval Theorem
Click For Summary

Discussion Overview

The discussion revolves around the Nested Interval Theorem, specifically examining its formulation and implications as presented in a textbook. Participants explore the conditions under which the theorem holds, including the nature of the intervals and the convergence of their diameters.

Discussion Character

  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant asserts that the theorem states if \( A_n = [a_n, b_n] \) is a sequence of closed intervals such that \( A_{n+1} \subseteq A_n \) for all \( n \in \mathbb{N} \), then the intersection \( \bigcap_{n \in \mathbb{N}} A_n \) should be empty, suggesting a flaw in the textbook's presentation.
  • Another participant reiterates the theorem's statement, emphasizing that the intersection should not be empty under certain conditions, specifically when the lengths of the intervals approach zero.
  • A further contribution highlights that for the theorem to hold, it is necessary that \( b_n - a_n \to 0 \) as \( n \to \infty \), using the example of intervals defined as \( A_n = [n, \infty) \) to illustrate a contradiction if this condition is not met.
  • One participant expands the discussion to a more general context, mentioning nested sequences of sets in a complete metric space with diameters approaching zero.

Areas of Agreement / Disagreement

Participants express disagreement regarding the correct interpretation of the Nested Interval Theorem, with some asserting that the intersection can be non-empty under specific conditions, while others question the textbook's formulation. The discussion remains unresolved with competing views on the theorem's validity.

Contextual Notes

Participants note that the theorem's validity may depend on additional conditions, such as the convergence of the interval lengths, which are not fully addressed in the initial statements.

pyfgcr
Messages
22
Reaction score
0
The Nested interval theorem: If An = [an, bn] is a sequence of closed intervals such that An+1 \subseteq An for all n \in N, then _{n \in n}\bigcapA = ∅.
I think of the case where a1=a2=...=an and b1=b2=...=bn for all n, hence every set A(n+1) will be the "subset" of A(n) and the intersection is the original closed interval. So I think the theorem in my textbook have some problem. Any correction for this ?
 
Physics news on Phys.org
pyfgcr said:
The Nested interval theorem: If An = [an, bn] is a sequence of closed intervals such that An+1 \subseteq An for all n \in N, then _{n \in n}\bigcapA = ∅.
I think of the case where a1=a2=...=an and b1=b2=...=bn for all n, hence every set A(n+1) will be the "subset" of A(n) and the intersection is the original closed interval. So I think the theorem in my textbook have some problem. Any correction for this ?

It should be:
If A_n=[a_n,b_n] is a sequence of closed intervals such that A_{n+1}\subseteq A_n for all n\in\mathbb{N}, then \bigcap_{n\in \mathbb{N}}A_n \neq \emptyset.
 
micromass said:
It should be:
If A_n=[a_n,b_n] is a sequence of closed intervals such that A_{n+1}\subseteq A_n for all n\in\mathbb{N}, then \bigcap_{n\in \mathbb{N}}A_n \neq \emptyset.


...and not only that: it must be also that \,b_n-a_n\xrightarrow[n\to\infty]{} 0\, , as \,A_n:=[n,\infty)\, would contradict.

DonAntonio
 
Or, more generally, a collection of nested sequence of sets in a complete metric space

with diameter approaching 0 as n-->00 .
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K