Is the O3 Molecule Polar Due to Fractional Charges and Nonlinear Geometry?

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Discussion Overview

The discussion centers on the polarity of the O3 molecule, exploring whether it is polar or non-polar. Participants examine the implications of molecular geometry, symmetry, and oxidation states on dipole moments.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant asks whether the O3 molecule is polar or non-polar and requests an explanation if it is polar.
  • Another participant notes that ozone has a symmetry group C2v, suggesting that the dipole moment along the C2 axis is generally non-vanishing, while dipole moments in perpendicular directions are zero.
  • A participant prompts further discussion by asking for opinions on the molecular structure of O3.
  • It is mentioned that the oxygen atoms in ozone have different oxidation states, leading to different fractional charges, and that the nonlinear geometry contributes to a non-vanishing dipole moment.

Areas of Agreement / Disagreement

Participants express differing views on the polarity of the O3 molecule, with some supporting the idea of a non-vanishing dipole moment due to geometry and oxidation states, while others focus on symmetry considerations. No consensus is reached.

Contextual Notes

The discussion involves assumptions about molecular geometry and oxidation states, as well as the implications of symmetry on dipole moments, which remain unresolved.

Indranil
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Is O3 molecule polar or non-polar? I am confused. If it is molar, could you explain why?
Thinking you.
 
Chemistry news on Phys.org
Ozone has symmetry group C2v. That means that the dipole moment along the C2 axis is non-vanishing in general, while the dipole moments in directions perpendicular to this direction must be 0.
 
Oxygen atoms are in different states of oxidation. Their fractional charges are different. Molecular geometry is nonlinear.
Hence, dipolar momentum is non-vanishing.
 

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