Is the Product Rule the Key to Finding h'(2)?

[tpcgreg]

Hello,It is given that h(x) = f(x)g(x). It then tells me to write a formula for h'(2).

I know that h'(x) = f'(x)g(x) + f(x)g'(x), using the product rule.

So I assumed that h'(2) = f'(2)g(2) + f(2)g'(2)

Is this correct? Does the product rule simply allow me to do this? It seems to simple.

Thanks in advance,

Greg

 

[noobilly]

Looks correct to me. You were expecting something really complicated?

 

[tpcgreg]

I'm in calculus 1, so this stuff is fairly new to me. Just making sure I wasn't missing something. Thanks!

 

[HallsofIvy]

Yes, if a function is given by f(x)= really complicated stuff with the letter "x" in it, then
f(2)= really complicated stuff with the letter "x" replaced by the number 2.

That has nothing to do with the derivative, per se, but with "function notation".