Is the Product Rule the Key to Finding h'(2)?

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Discussion Overview

The discussion revolves around the application of the product rule in calculus to find the derivative of a function defined as the product of two other functions, specifically evaluating h'(2) for h(x) = f(x)g(x). The scope includes conceptual understanding and application of differentiation rules.

Discussion Character

  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • Greg states that h'(x) = f'(x)g(x) + f(x)g'(x) using the product rule and questions if this is correct for finding h'(2).
  • Some participants affirm that Greg's application of the product rule appears correct and question if he expected a more complex solution.
  • Greg expresses uncertainty about the simplicity of the product rule and seeks reassurance that he is not overlooking anything important.
  • Another participant comments on the nature of function notation, indicating that evaluating f(2) involves substituting 2 into the function, which is separate from the derivative process.

Areas of Agreement / Disagreement

There is a general agreement on the correctness of applying the product rule, but some uncertainty remains regarding the simplicity of the process and the understanding of function notation.

Contextual Notes

Participants have not fully explored the implications of the functions f(x) and g(x), nor have they provided specific forms for these functions, which may affect the evaluation of h'(2).

tpcgreg
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Hello,It is given that h(x) = f(x)g(x). It then tells me to write a formula for h'(2).

I know that h'(x) = f'(x)g(x) + f(x)g'(x), using the product rule.

So I assumed that h'(2) = f'(2)g(2) + f(2)g'(2)

Is this correct? Does the product rule simply allow me to do this? It seems to simple.

Thanks in advance,

Greg
 
Last edited:
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Looks correct to me. You were expecting something really complicated?
 
I'm in calculus 1, so this stuff is fairly new to me. Just making sure I wasn't missing something. Thanks!
 
Yes, if a function is given by f(x)= really complicated stuff with the letter "x" in it, then
f(2)= really complicated stuff with the letter "x" replaced by the number 2.

That has nothing to do with the derivative, per se, but with "function notation".
 

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