Is the Reaction in Equilibrium Given Kc and Q Values?

[oceanflavored]

Homework Statement

Determine whether or not each of the following system is in equilibrium. If the system is not in equilibrium, predict whether it will proceed in the forward or reverse direction:
2 H2(g) + O2(g) ---> 2H2O(g)
and Kc (equilibrium constant) is 9.1 x 10^80
and the concentrations are H2: 3 x 10^-30 M...for O2: 2.2 x 10^-24...for 2H2O: 0.0180 M

Homework Equations

To compare a system to equilibrium, you have to compare K to Q. where Q is [products]^coeffecients / [reactants]^coeffecients
and if Q = K, the reaction is at equilibrium...if Q < K, the reaction will move in the forward direction...and if Q > K, the reaction will move in the reverse direction.

The Attempt at a Solution

so i solved it like this...
[0.0180]^2 / [3 x 10^-30]^2[2.2 x 10-24] and i got...1.64 x 10^79 for Q
and since Q < K i said the reaction would move in the forward direction

and here's where the problem comes in
the book says: that for Q i should get 9.1 x 10^80, meaning that Q would be equal to K and reaction would be in equilibrium.

please help me. am i inputing the things in my calculator wrong? or is the book wrong? thanks muchhh

 

[oceanflavored]

come on guysssssss.
you can do this.
please.
&gracias.

 

[hage567]

Well, I'm no chemist, but I think your calculation for Q is correct. I can't see a mistake in it. Are you sure you copied everything correctly? Perhaps the book is wrong.

 

[oceanflavored]

Thanks!

i'm positive i copied everything correctly.&i did it like 10 times.
so the book is probably wrong.
thanks so much hage657