Is the Slope of the Wheelchair Ramp Too Steep for Young Children?

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Homework Help Overview

The discussion revolves around the assessment of a newly installed wheelchair ramp at a nursery, specifically evaluating whether the slope is too steep for young children using wheelchairs. The problem involves calculating forces related to gravity, friction, and the applied force required to ascend the ramp.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of various physics equations to determine the forces acting on the wheelchair as it moves up the ramp. There are questions about the correct identification of the applied force and the interpretation of the results in relation to the ramp's steepness.

Discussion Status

Participants are actively engaging with the problem, sharing calculations and questioning the validity of their approaches. Some guidance has been provided regarding the interpretation of forces, particularly the applied force needed to maintain movement up the ramp. There is an ongoing exploration of whether the calculated forces indicate that the slope is too steep.

Contextual Notes

There is a specific constraint mentioned regarding the maximum force that can be applied (50N), which is central to the discussion about the ramp's steepness. Participants are also considering the effects of friction and gravity in their calculations.

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Homework Statement



There was a new wheelchair ramp installed at a nurserey. It was built for young children with wheelchairs to go up instead of the stairs and it was made to not be too difficult to get up. If the required force is not more than 50N like the testers say. If the weight of one child+wheelchair is 30kg, and the slope of the ramp is 5degrees, is the slope too steep? The friction with everything regarding wheels is by coefficient of uk = .10

Homework Equations



Fg=mg
Fnet=Fa-Ff-F||
F||=Fgsintheta
Fperpen=Fgcostheta

The Attempt at a Solution



I have found fg by using Fg=mg
Fg=30(9.8)
Fg=294.3

then I found the F||=Fgsintheta
F||=294.3sin5
F||=25.6

Fperpen=Fgcostheta
Fperpen=294.3cos5
Fperpen=293.2


So now I was thinking to use the Fnet=Fa-Ff-F||


But I don't know what to find or anything to actually know if its too step or not, I don't know if that above equation is correct.



thanks
 
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hi homevolend! :smile:

(have a mu: µ and a theta: θ and a degree: ° and try using the X2 icon just above the Reply box :wink:)
homevolend said:
I have found fg by using Fg=mg
Fg=30(9.8)
Fg=294.3

then I found the F||=Fgsintheta
F||=294.3sin5
F||=25.6

Fperpen=Fgcostheta
Fperpen=294.3cos5
Fperpen=293.2


So now I was thinking to use the Fnet=Fa-Ff-F||

yes, that's fine :smile:, except i don't understand what your Fa is

now use the normal force and µ to find the friction force :wink:
 
Ok I am still not sure if I am using the correct formula to do the Fnet.

I did Fnet=Fa-Ff-F||

Fnet=50-29.43-25.6

Fnet=14.7


But that does not seem correct, I do not think I am using the right formula, Then once I have the fnet I do not know how or what else to find to say if it is steep enough or not.
 
hi homevolend! :smile:

(just got up :zzz: …)
homevolend said:
I did Fnet=Fa-Ff-F||

Fnet=50-29.43-25.6

oh i see … Fa is the applied force

no, you're misunderstanding the question, Fa is not 50, Fa is the minimum force needed to keep the wheelchair moving …

so find what Fa is from your Fnet = 0 formula, and then answer yes/no is it > 50 (which would mean the slope is too steep)? :smile:
 
Got it I used the 0=Fa-Fk-F||

Got 55, so yes it is too steep because it cannot be more than 55.
"Can be no more than 50N" so does that mean its too steep?
 
homevolend said:
Got it I used the 0=Fa-Fk-F||

Got 55, so yes it is too steep because it cannot be more than 55.
"Can be no more than 50N" so does that mean its too steep?

Yup! :smile:

overcoming both gravity and friction would require 55 N, so the slope is too steep for someone who can only apply 50 N
 
Thanks for the help tim.
 

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