The discussion revolves around the analysis of forces acting on a package on a conveyor belt inclined at an angle, focusing on trigonometric components of these forces. Participants are examining the relationship between gravitational forces, friction, and the normal force in the context of steady motion.
Some participants have offered guidance on drawing a free body diagram and identifying the components of forces acting on the box. There is an ongoing debate about the correctness of the trigonometric functions used in the force equations, with differing interpretations being explored.
There is mention of the assumption that friction is at its limiting value and the implications of the box moving at a steady velocity, which raises questions about the total force required to maintain this state. Participants are also addressing potential misunderstandings regarding the definitions of normal and parallel forces in the context of the incline.
Start with a free body diagram of the package on the slope. Draw the box and draw vectors representing the forces acting on it.Aariz said:
You had written down an equation for force:Aariz said:
Apparently, this is the component of net force acting on the box in the direction parallel to the ramp, diagonally downward. This under the assumption that friction is at its limiting value (just on the verge of slipping).Aariz said:
According to the angle labeled as ##\theta## in the diagram? I think the trig functions are in your description are flipped. ##mg \sin \theta ## is the normal force, and the weight of the box parallel is to the slope is ##mg \cos \theta##.jbriggs444 said:
jbriggs444 said:
Yes, flipped.erobz said: