Is the Use of F=γma Correct in Special Relativity Calculations?

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athrun200
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Homework Statement


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Homework Equations





The Attempt at a Solution


Can I do it like this:
[itex]F=γma[/itex]
[itex]F=γm\frac{dv}{dt}[/itex]
[itex]F=γm\frac{dv}{ds}\frac{ds}{dt}[/itex]
[itex]v\frac{dv}{\sqrt{1-\frac{v^2}{c^2}}}=\frac{F ds}{m}[/itex]

The finial answer will becom
v=[itex]\frac{\sqrt{2c^2mFx-Fx}}{mc}[/itex]

What's wrong?
 
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[tex]F=\frac{dp}{dt}[/tex]
[tex]F=\frac{d}{dt}(\gamma mv)[/tex]
[tex]F=\gamma m \frac{dv}{dt} + mv\frac{d\gamma}{dt}[/tex]

Because gamma is a function of v and varies with time, you run into problems. You should still be able to solve it this way if you take the extra term into account, but it's a lot more work than energy conservation method.