Is There a Relation Between cos5A and cosA, sin4A and sinA?

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SUMMARY

This discussion focuses on the relationships between trigonometric functions, specifically cos5A and cosA, as well as sin4A and sinA. Users explored deriving formulas using the angle sum identities and binomial coefficients, with particular emphasis on the complexity of expressing these functions in simpler trigonometric ratios. The conversation highlighted the challenges of working with fractional angles and the limitations of algebraic manipulation for non-integer multiples. Participants also recommended resources like WolframAlpha for solving related problems.

PREREQUISITES
  • Understanding of trigonometric identities, specifically angle sum formulas.
  • Familiarity with binomial coefficients and combinations, denoted as C(n, r).
  • Basic knowledge of algebraic manipulation involving trigonometric functions.
  • Experience with fractional angles in trigonometry.
NEXT STEPS
  • Study the derivation of trigonometric identities using angle sum formulas.
  • Learn about binomial expansions and their applications in trigonometry.
  • Explore the use of WolframAlpha for solving complex trigonometric equations.
  • Investigate the properties of fractional angles in trigonometric functions.
USEFUL FOR

Students studying trigonometry, educators teaching trigonometric identities, and anyone seeking to deepen their understanding of advanced trigonometric relationships.

Celluhh
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is there a relation between the numerical answers of cos5A and cosA?

sin4A and sinA?

i want to work backwards, if it is possible. tried deriving a formula by myself, but couldnt.:(
 
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\begin{array}{l}<br /> \sin na = {}^n{C_1}{\cos ^{n - 1}}\sin a - {}^n{C_3}{\cos ^{n - 3}}a{\sin ^3}a + {}^n{C_5}{\cos ^{n - 5}}a{\sin ^5}a... \\ <br /> \cos na = {\cos ^n}a - {}^n{C_2}{\cos ^{n - 2}}a{\sin ^2}a + {}^n{C_4}{\cos ^{n - 4}}a{\sin ^4}a... \\ <br /> \end{array}

Where a is the angle and n an integer.
 
I think, you can use the sum of two angles approach

Sin4A = 2 Sin2A Cos2A
= 2 (2 SinA CosA) Cos2A
= 4 SinA CosA (Cos²A - Sin²A)
= 4 SinA CosA (1 - 2Sin²A)
= 4 CosA (SinA - 2 Sin³A)
= 4 √(1 - Sin²A)(SinA - 2 Sin³A)

Similar approach can be taken for other one.
 
Oh ok thank you !
 
What about for fractions ? For example sin1/3 x?
 
For fractions it's essentially not doable, except for n=2,3,4, because of the algebra involved.
 
Did you have a problem with my general formulae?
 
@studiot, no that's not it but it's hard to memorise it and it's not one of the formulas learned in school for
Now , so I can't exactly use it in my exam ! Thanks a lot though !
 
Um wait what is C1 ,C2 etc...
 
  • #10
They are symbols for combination. Also written as C(n,1).
If you have not studied permutations, combinations, factorial yet, then you won't understand them.
 
  • #11
Oh I see yep I'm only at the double angle formulae level ... And having problems with expressing cos4a or others in the form of simple trigo ratio eg. Cosa. Does anyone have any online website to recommend that solves this kind of problems ?
 
  • #12
Have you ever heard of wolframalpha? I am not sure if I should post links in this forum, but you can google it.
 
  • #13
These are the binomial coefficients also written


\left( {\begin{array}{*{20}{c}}<br /> n \\<br /> r \\<br /> \end{array}} \right)

They are normally studied before trigonometry.
 

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