Is there a way to simplify this integral involving an exponential function?

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The discussion centers on simplifying the integral ##\int_a^b{f(t)e^{t}}dt##, given that ##\int_a^b{f(t)dt}=f_0##. Participants conclude that without additional information about the function ##f(t)##, specifically its differentiability and form, the integral cannot be evaluated directly. The integral ##\int_a^b{f(a)e^{t}}dt## simplifies to ##f(a)[e^b - e^a]##, but the second integral requires more context about ##f(t)## to apply techniques like integration by parts effectively.

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BillKet
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Hello! I have a function ##f(t)## such that ##\int_a^b{f(t)dt}=f_0##. Is there a way to calculate (or bring it to a simpler form) ##\int_a^b{f(a)e^{t}}dt##? Thank you!
 
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May i ask : does the exercise say that ##f(t)## is differentiable? the second integral contains##f(a)##?or perhaps it is ##f(t)##? what is your effort so far?
 
BillKet said:
Hello! I have a function ##f(t)## such that ##\int_a^b{f(t)dt}=f_0##. Is there a way to calculate (or bring it to a simpler form) ##\int_a^b{f(a)e^{t}}dt##? Thank you!
As written, ##\int_a^b{f(a)e^{t}}dt = f(a)[e^b - e^a]##.
 
etotheipi said:
As written, ##\int_a^b{f(a)e^{t}}dt = f(a)[e^b - e^a]##.
Ah sorry, the questions should be about ##\int_a^b{f(t)e^{t}}dt##
 
trees and plants said:
May i ask : does the exercise say that ##f(t)## is differentiable? the second integral contains##f(a)##?or perhaps it is ##f(t)##? what is your effort so far?
It should be ##f(t)##. It is not an exercise, it is something obtained from a physics experiment, but I would say that yes, the function is differentiable. I can't say that I had many ideas, I was hoping there is probably some formula I don't know about that can be applied, as there is not much to do here with basic integration techniques.
 
BillKet said:
Ah sorry, the questions should be about ##\int_a^b{f(t)e^{t}}dt##
I don't think the integral can be evaluated without knowing more about f(t).
 
You could use the fundamental theorem of calculus for the first integral to get values for ##a## and ##b## for the antiderivative, let us say it ##F##, so you have ##F(b)-F(a)=f_0##.

We are talking here about definite integrals so for the second integral, someone i think would need to express it in terms of ##F(a),F(b)##, using integration by parts i think does not lead to computing it.

I want to say that there are ways to compute some integrals involving exponentials, polynomials, n-th roots, square roots and others, but here ##f(t)## is given without saying whether it has other properties or is of a form as for example the ones i said in this post.
 

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