Is This a Long or Short Rossby Wave at 35o N?

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SUMMARY

The discussion centers on determining whether a Rossby wave with a wavelength of 500 km at 35° N latitude is classified as a long or short wave. The Rossby Radius of Deformation (RD) is calculated to be 2.38 x 106 m. The key comparison involves evaluating the x-component of the wave number (kx) against RD, where kx is derived from the wavelength using the formula k = 2π/λ. The participant seeks clarification on converting kx from radians per meter to meters for proper comparison.

PREREQUISITES
  • Understanding of Rossby waves and their significance in oceanography.
  • Familiarity with the Rossby Radius of Deformation (RD) and its calculation.
  • Knowledge of wave number and its relationship to wavelength.
  • Basic concepts of unit conversion, particularly between radians and meters.
NEXT STEPS
  • Study the derivation and implications of the Rossby Radius of Deformation (RD).
  • Learn about the significance of wave number (k) in wave mechanics.
  • Research methods for converting angular measurements (radians) to linear distances.
  • Explore the impact of latitude on wave propagation in oceanic systems.
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Students and researchers in oceanography, meteorology, and environmental science who are analyzing wave dynamics and their implications in fluid dynamics.

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Homework Statement


Consider a Rossby wave propagating in a homogeneous ocean with a water depth of 4,000m at 35o N latitude. If the wave length of this wave is 500km, is this a long or short Rossby wave?

Homework Equations


shortwaves: |kx-1| <<RD
longwaves: |kx-1| >> RD

kx is the x-component of the wave number, k. wavenumber = 2pie/λ
-kx = k

RD = Rossby Radius of Deformation = (gh)1/2 / ƒ
where ƒ is the Coriolis parameter.

The Attempt at a Solution


RD = Rossby Radius of Deformation = (gh)1/2 / ƒ = 2.38 x 106m. ƒ is in seconds-1, RD is in meters.

-kx = k = 2Pie / λ. = 1.26 x 10-5 rad m-1.

I want to compare |kx-1| to RD. How do I change my units for kx?? Because I cannot compare something in rad*m-1 to meters.

I think that I have to change the radians to a distance, using the Earth's radius (6,371 km), at a latitude of 35o North. This is where I am stumped??
 
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One radian on the Earth = 1 Earth radius in length right?
 

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