Is this an energy conversion error?

In summary: In the case of an ideal gas, the internal energy is purely kinetic. Therefore, the air molecules do gain kinetic energy when heated. This kinetic energy is then expressed in the form of movement, which we can call "translation". In summary, the conversation discusses the concept of heat energy converting to kinetic energy in the context of a twister created by a lit candle. It is explained that the heated air becomes less dense and rises, causing the twister to twist. The difference between internal kinetic energy and kinetic energy in the translation sense is also addressed.
  • #1
AgentPancake
9
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Lets say we had a twister, below it there's a lit candle, after a while the blades of the twister move. I know its because the air around the flame is heated and so the air rises. But can we say heat energy converts to kinetic energy in this situation. Becuause its not becuz the air got heated so it moved it is because the air there got lighter(less dense) so the air above it moved down and it moved up. I mean let's say we had a little particle in a vacuum its not go going to move up just because its heated right?
 
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  • #2
AgentPancake said:
Lets say we had a twister, below it there's a lit candle, after a while the blades of the twister move. I know its because the air around the flame is heated and so the air rises. But can we say heat energy converts to kinetic energy in this situation. Becuause its not becuz the air got heated so it moved it is because the air there got lighter(less dense) so the air above it moved down and it moved up. I mean let's say we had a little particle in a vacuum its not go going to move up just because its heated right?
We have to be careful here as macroscopic quantities, such as pressure and density don't really work when we have a small number of particles - we need many particles to work with these quantities.

What we can say is this: The air in the immediate vicinity of the candle is heated and gains kinetic energy. Therefore, the air moves faster and the same number of air particles occupy a greater volume. Thus, the density of the air decreases. The now less-dense air surrounding the candle rises through the surrounding more-dense air. This "block" of rising air collides with the blades of the twister and causes the twister to, well, twist.

Another explanation, without requiring density is that when the air is heated it gains more kinetic energy and can then (via brownian motion) move to a higher gravitational potential, i.e. move upwards.
 
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  • #3
I am not sure we can say that when such air is heated up it gains kinetic energy, not in the context that you are trying to address it...after all, you could also heat up gas inside a balloon tied down to a chair...is the balloon going anywhere? is the air going anywhere? did it gain kinetic energy?

I think that you are forgetting that the work require to move the heated air is being done by the weight of the surrounding (denser) air and gravity...nothing to do with the candle itself...you could let helium (without being heated up) out of a can and it will also move up without having to "gain kinetic energy" or being "pushed" by a candle.

So, you are "correct" to think that if your heated air was in a vacuum, it wouldn't move up since it wouldn't be surrounded by denser air to push it up.
 
  • #4
gsal said:
...after all, you could also heat up gas inside a balloon tied down to a chair...is the balloon going anywhere? is the air going anywhere? did it gain kinetic energy?
Whilst the balloon doesn't gain kinetic energy, the air inside the balloon certainly does. After all, we know that the average kinetic energy of an ideal gas is proportional to the temperature. Therefore, if you increase the temperature of a volume of gas, the gas molecules will, on average, have more kinetic energy.
gsal said:
I think that you are forgetting that the work require to move the heated air is being done by the weight of the surrounding (denser) air and gravity...nothing to do with the candle itself...you could let helium (without being heated up) out of a can and it will also move up without having to "gain kinetic energy" or being "pushed" by a candle.
The point here it that the helium filled balloon started less dense. However, for the air to become less dense, it had to gain kinetic energy. How else to you propose that the density of heated air decreases?
gsal said:
So, you are "correct" to think that if your heated air was in a vacuum, it wouldn't move up since it wouldn't be surrounded by denser air to push it up.
Heat air in a vacuum?! Are you serious? A vacuum, by definition, will be [classically] empty and have no air in it.
 
  • #5
Whilst the balloon doesn't gain kinetic energy, the air inside the balloon certainly does. After all, we know that the average kinetic energy of an ideal gas is proportional to the temperature. Therefore, if you increase the temperature of a volume of gas, the gas molecules will, on average, have more kinetic energy.

But this is internal kinetic energy, not kinetic energy in the translation sense that would produce motion! It is not like the candle is actually "pushing" the air, like I said before...it is just heating it up and raising its temperature...the candle is NOT causing the air to move! I think this is the context of kinetic energy the OP was concerned about.

Heat air in a vacuum?! Are you serious? A vacuum, by definition, will be [classically] empty and have no air in it.

Yes, I am "serious"...just trying to help the OP visualize the problem that if you take the surrounding air, then the heated air does not move...let the OP be the judge of such visualization.
 
  • #6
gsal said:
But this is internal kinetic energy, not kinetic energy in the translation sense that would produce motion! It is not like the candle is actually "pushing" the air, like I said before...it is just heating it up and raising its temperature...the candle is NOT causing the air to move! I think this is the context of kinetic energy the OP was concerned about.
Just to clarify, I never said that the candle "pushes the air upwards".

There is no such quantity known as "internal kinetic energy". There is a quantity known as internal energy, which is composed of kinetic energy and potential energy. The kinetic energy accounts of the translational, rotational and vibrational motion of the molecules. Kinetic energy is always associated with motion, so I don't understand what you are referring to.

Answer me this: When the candle increases the temperature of the air, does the kinetic energy of the air increase?

Second question: If the candle isn't causing the air to move, would it still move upwards if we removed the candle?

gsal said:
Yes, I am "serious"...just trying to help the OP visualize the problem that if you take the surrounding air, then the heated air does not move...let the OP be the judge of such visualization.
You cannot have air inside a vacuum, nor can you discuss the notion of macroscopic temperature inside a vacuum, certainly not the temperature of a gas.
 
  • #7
Without getting into a semantics war, I am going to reply one more time to you Hootenanny and that's it; after all, I think by now, the OP most probably got an answer to his/her question.

Hootenanny:
The main thing that I was trying to indicate (and separate) is that when the OP asked if the heat from the candle turned into kinetic energy, which then caused the "bubble" of hot air to move up...clearly, he/she had in mind that kind of kinetic energy that is typically related to translation motion of an entire body (e.g., a ball thrown, a bullet shot, etc...think kinetic energy in ridig bodies) and NOT the kinetic energy of the individual particles of the gas...in other words, kinetic energy as defined http://en.wikipedia.org/wiki/Kinetic_energy" .

There is no such quantity known as "internal kinetic energy". There is a quantity known as internal energy, which is composed of kinetic energy and potential energy. The kinetic energy accounts of the translational, rotational and vibrational motion of the molecules. Kinetic energy is always associated with motion, so I don't understand what you are referring to.

No, the kinetic energy included into the internal energy actually excludes the kinetic energy due to motion of the entire system. Please refer to http://en.wikipedia.org/wiki/Internal_energy" definition and read carefully.

Answer me this: When the candle increases the temperature of the air, does the kinetic energy of the air increase?
Yes, the kinetic energy that is part of the internal energy, also known as THERMOdynamic energy, increases...but this has nothing to do with the kinetic energy that entire "bubble" of hot air could acquire as it moves up due to external forces (surrounding denser air pushing it up).

Second question: If the candle isn't causing the air to move, would it still move upwards if we removed the candle?
The candle is not the SOLE reason why the "bubble" of hot air moves up...the candle makes the "bubble" of hot air lower its density, but it is the fact that such "bubble" of hot air is surrounding by denser air under gravity that actually pushes the "bubble" of hot air up...this is nothing but Archimedes principle all over again.

And that's when I brought up the "bubble" of helium example...if you release a balloon of helium, you don't need a candle since helium already has lower density than air and so, it gets pushed up.

And that's when I brought up the example of a "bubble" (don't be a purist and just bare with me) of air surrounded by nothing (in vacuum?)...if you heat it up, it is not going anywhere...

That's all.

Cheers.

gsal
 
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  • #8
gsal said:
Without getting into a semantics war, I am going to reply one more time to you Hootenanny and that's it; after all, I think by now, the OP most probably got an answer to his/her question.
Just to clarify: it was you that began this "semantics war" by saying that I was incorrect in asserting that the kinetic energy of a gas increases as its temperature increases.
gsal said:
The main thing that I was trying to indicate (and separate) is that when the OP asked if the heat from the candle turned into kinetic energy, which then caused the "bubble" of hot air to move up...clearly, he/she had in mind that kind of kinetic energy that is typically related to translation motion of an entire body (e.g., a ball thrown, a bullet shot, etc...think kinetic energy in ridig bodies) and NOT the kinetic energy of the individual particles of the gas...in other words, kinetic energy as defined http://en.wikipedia.org/wiki/Kinetic_energy" .
I'm sorry, but this is where you're flat out wrong. There are no "types" of kinetic energy - kinetic energy is kinetic energy. It doesn't matter if its an oil tanker, a plant, a fly, a car, a molecule or a proton. If it moves, it has kinetic energy. Obviously, the interpretation of an objects motion and hence kinetic energy, depends on the context. However, I reiterate: There are no "types" of kinetic energy.
gsal said:
No, the kinetic energy included into the internal energy actually excludes the kinetic energy due to motion of the entire system. Please refer to http://en.wikipedia.org/wiki/Internal_energy" definition and read carefully.
I never said it didn't. Temperature, is defined in the rest frame of the system under consideration. This is well known. You'll find no contradictory comment in my above posts. I'll say again, there are no "types" of kinetic energy.
gsal said:
Yes, the kinetic energy that is part of the internal energy, also known as THERMOdynamic energy, increases...but this has nothing to do with the kinetic energy that entire "bubble" of hot air could acquire as it moves up due to external forces (surrounding denser air pushing it up).
I never said it did. See my above comments. At some point you have to refer to the kinetic energy of the air molecules, how else are you to explain how the air becomes less dense?
gsal said:
And that's when I brought up the example of a "bubble" (don't be a purist and just bare with me) of air surrounded by nothing (in vacuum?)...if you heat it up, it is not going anywhere...
I'm not being a purist, this just doesn't make any sense whatsoever and is a very poor analogy to what is or isn't happening.
 
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1. What is an energy conversion error?

An energy conversion error is a mistake or discrepancy that occurs during a process of converting one form of energy into another. This can happen due to various factors such as measurement error, equipment malfunction, or incorrect calculations.

2. How can I identify an energy conversion error?

There are a few signs that may indicate an energy conversion error, including unexpected or inconsistent results, abnormal readings, or a discrepancy between the input and output energy values. Conducting multiple trials and comparing results can also help identify potential errors.

3. What are the consequences of an energy conversion error?

An energy conversion error can have significant consequences, especially in scientific research or industrial processes. It can lead to inaccurate data, faulty conclusions, and potentially dangerous situations in certain industries such as energy production or transportation.

4. How can I prevent energy conversion errors?

To prevent energy conversion errors, it is essential to have proper training and understanding of the conversion process. Double-checking calculations, using reliable equipment, and conducting regular maintenance can also help minimize the risk of errors. It is also crucial to have a thorough understanding of the theory and principles behind energy conversion.

5. What should I do if I suspect an energy conversion error?

If you suspect an energy conversion error, the first step is to carefully review your data and calculations to identify any potential mistakes. It may also be helpful to consult with colleagues or seek assistance from experts in the field. If the error is confirmed, it is essential to address and correct it before proceeding with further experiments or processes.

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