Is this assumption correct? (dynamic friction)

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SUMMARY

A particle of mass M slides on a horizontal surface with a dynamic friction coefficient of μ = 0.4, moving towards a wall at 6 m/s. The deceleration due to friction is calculated as a = 4 m/s². Using the SUVAT equations, the particle strikes the wall after approximately 0.1775 seconds with a final velocity of 5.29 m/s. An alternative approach using the equation s = ut + 1/2at² could simplify the calculations.

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  • Knowledge of SUVAT equations for motion analysis
  • Basic arithmetic and algebra skills for solving equations
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A particle of mass M slides on a horizontal surface with coefficient of (dynamic) friction
μ = 0.4. At time t = 0 it is 1m from a vertical wall, moving at 6 m/s perpendicularly towards it. When does it strike the wall? ( You may assume it is less than 1 second)

Homework Equations



friction = μ x N

where N is the normal force

suvat equations

The Attempt at a Solution



friction = μ x N

M x a = μ x M x g where g = 10 m/s^2

a = 0.4 x g = 4 m/s^2

I want to know if I can take this as a deceleration? Therefore hitting the wall with a velocity of :

v^2 = u^2 + 2as where u = 6 m/s s = 1m a = -4 m/s^2

v = 5.29 m/s

and where the time taken is :

v = u + at

t = 0.1775 seconds
 
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I've not checked your arithmetic, but your method looks fine to me.

One minor point: you have used two SUVAT equations here. However, if you would have used the equation s = ut + 1/2at2, you could have cut your working in half.
 

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