# Is this equivalent to the Pythagorean Theorem?

1. Jun 29, 2012

### Quine!

I don't see the reasoning behind this statement.

I tried some simple algebra on this statement and couldn't get Pythag to fall out of it. Can someone figure out a derivation for this?

Last edited by a moderator: May 6, 2017
2. Jun 29, 2012

### Muphrid

That's not what the page says. It says,

$$AB^2 = AC^2 + CB^2$$

A, B, and C are not variables. $AB$ represents the length between points A and B. You should read $AB^2$ as a single length being squared.