Is this example of Bond Energy correct?

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SUMMARY

The discussion centers on the accuracy of bond energy calculations in a polymerization example, specifically example 2.9. It is established that polymerizations are typically exothermic, resulting in a negative reaction energy. The correct enthalpy change calculation is presented as +680 - 740 = -60 kJ/mol, clarifying that the misunderstanding may stem from a misinterpretation of "reaction energy." The distinction between enthalpy change and bond energy is emphasized, confirming the accuracy of the provided calculations.

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esale

Homework Statement


[/B]
ex2_10.JPG

(see attachments for example 2.9)

Homework Equations


[/B]
be_equation.JPG


The Attempt at a Solution


As far as I have read and understood, most polymerizations (such as the one in this example) are exothermic. If this is the case, shouldn't this produce a negative (-) reaction energy? And the equation they should have used is the one I included in section two (2)?

Thank you in advance for any help.

-E
 
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Forgot to add example 2.9...

ex2_9.jpg


And Table 2.2

table2_2.JPG
 
Last edited by a moderator:
Unless they are defining "reaction energy" differently from usual, the blue box is wrong. You input the energy to break the C=C bond, and the energy of forming two C-C bonds is given out. So the enthalpy change is +680 - 740 = -60 kJ/mol. They may be confused by the fact that
ΔHrxn = Hproducts - Hreactants
But this is not equal to BEproducts - BEreactants
Relative to the state where all bonds are broken, H = -BE. So your white box is right.
 
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mjc123 said:
Unless they are defining "reaction energy" differently from usual, the blue box is wrong. You input the energy to break the C=C bond, and the energy of forming two C-C bonds is given out. So the enthalpy change is +680 - 740 = -60 kJ/mol. They may be confused by the fact that
ΔHrxn = Hproducts - Hreactants
But this is not equal to BEproducts - BEreactants
Relative to the state where all bonds are broken, H = -BE. So your white box is right.

Thank you for your answer!
 

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