Is the statement 'int x^n from 0 to 1 = 1/(n + 1)' true?

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The statement "int x^n from 0 to 1 = 1/(n + 1)" is true for n greater than -1. As n approaches infinity, the integral approaches zero, reflecting that x^n diminishes for values of 0 < x < 1. For n less than 0, the statement does not hold true. The discussion emphasizes the importance of n's value in determining the validity of the integral. Overall, the integral's behavior is consistent with the properties of exponential decay as n increases.
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int x^n from 0 to 1 = 1/(n + 1)

But as n approaches infinity the answer becomes zero.
 
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Yep. And if you look at x^n for some number 0<x<1 and 0<n, x^n will get smaller as n increases. It's only natural to see the integral get smaller as well.
 
Ok, thanks.
 
cstvlr said:
int x^n from 0 to 1 = 1/(n + 1)

But as n approaches infinity the answer becomes zero.

It is true as long as n &gt; -1. For n < 0, it is not true.
 
Last edited:
Mute said:
It is true as long as n \geq 0. For n < 0, it is not true.
Correction: It is true as long as n > -1, not zero.
 
D H said:
Correction: It is true as long as n > -1, not zero.

Corrected. Thanks. I forgot to edit that when I decided not to talk only about integers.
 

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