Is This Stopping Distance Formula Accurate for Physics Projects?

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SUMMARY

The stopping distance formula discussed is valid and can be expressed as d = V^2/(2g(f + G)), where d is the braking distance, V is the initial vehicle speed, g is the acceleration due to gravity, f is the coefficient of friction, and G is the roadway grade as a percentage. This formula is derived from standard equations of motion, considering factors such as force, mass, and friction. It is crucial to use correct units and understand the limitations of the formula, particularly regarding the grade's impact on stopping distance. Additional considerations for the poster include reaction time and wheel lockup effects.

PREREQUISITES
  • Understanding of basic physics concepts such as force and acceleration
  • Familiarity with the coefficient of friction and its application
  • Knowledge of standard equations of motion in physics
  • Ability to interpret roadway grade and its effects on motion
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  • Research the derivation of the stopping distance formula from basic physics principles
  • Explore the impact of reaction time on stopping distances in real-world scenarios
  • Investigate the effects of different coefficients of friction on braking performance
  • Examine the relationship between roadway grade and vehicle dynamics in braking
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Students in physics, educators preparing instructional materials, and anyone involved in automotive safety and engineering projects focused on braking distances and vehicle dynamics.

NewDarkAge
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Hi

I'm doing a poster on stopping distances for Physics, but it's a topic we haven't really discussed yet in the lessons. In my research I found this formula:

"d = V^2/(2g(f + G))

Where:
d = Braking Distance
g = Acceleration due to gravity
G = Roadway grade as a percentage;
V = Initial vehicle speed
f = Coefficient of friction between the tires and the roadway"

I just wanted to check with you guys whether this is a valid formula as I haven't found it anywhere else. Also, I was wondering if you could give me any ideas for what to include in the poster; I'm really looking for formulae relating different factors that affect braking distance.

I hope this all makes sense, and thanks very much for your time

S
 
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The equation looks about right.

If you start with one of the standard equations of motion and ignore the grade you can get to this equation reasonably easily..

d = V2 /2gμ

where
d = stopping distance
V = Initial velocity
g = acc due to gravity
μ = coefficient of friction

Along the way you use:

force = mass * acceleration
and
friction force = Normal force * coefficient of friction
which is equivalent to
friction force = Mass * g * coefficient of friction

Note how the definition of coefficient of friction relates vertical to horizontal forces. So (without doing the maths) it's not unreasonable that u term might be modified by the grade which is also expressed as a ratio of vertical to horizontal.

Perhaps another person fancies doing the full proof for you.
 
You need to be careful to use the correct units in these equations and the range of validity (eg, G is derived from the small angle approximation of the sine of the grade). Have a look at the following document for a bit more detail ... https://engineering.purdue.edu/~flm/CE%20361_files/chapter1_2_notes_.pdf (around about Problem 2.21).

A couple of items to think about (depending upon what the intent of the poster is) are reaction time (If it takes you 1.5 seconds to react how far will the car travel before you even hit the brakes!) and wheel lockup (you want to skedaddle away from having an accident not skidaddle into one)
 
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