# Is water level the same after an anchor is thrown from a boat?

1. Aug 3, 2012

### jamesbiomed

1. The problem statement, all variables and given/known data

(5) A person sitting in a boat floating on a small pond throws a heavy anchor overboard. Does the level of the pond rise, fall, or stay the same? Explain.

2. Relevant equations

FB=mass of fluid displaced times g
Fnety=Fb-mg

3. The attempt at a solution

Theoretically, the pond level should stay the same. For the boat/man system after the anchor toss, the force of gravity will be less, because the mass of the boat/man system is less without the anchor. The buoyant force since it is floating is equal to the weight of the fluid displaced. As the anchor is tossed from the boat, there will be a shift in the net force up in the positive y-direction (assuming up is positive) causing the boat to rise relative to the water, and a portion of the water once displaced by the boat to return. This will cause an overall drop in water level.
However, when the anchor is thrown in, it will sink, until it reaches the bottom, and its exact mass will displace the same mass of water, which will cause a rise in the pond level exactly the mass of the anchor.

...I wrote that based on my verbal understanding of buoyant force. But what I'm struggling with is exactly how buoyant force will affect the boat after the anchor is tossed. Like I said, it will rise so that the amount of fluid it displaces is less. But how much less? The buoyant force will decrease, because the mass of the water displaced will decrease. I know F net y=Fb-fg. So fg is going to decrease, which will cause F net y to increase. But Fb will also decrease. So how can I better explain this, and determine precisely if the amount displaced by the anchor will equal the change due to the boat being lighter?

Sorry for the length...

2. Aug 3, 2012

### Staff: Mentor

Consider the boat by itself (no anchor yet). If you put an anchor in the boat, how much additional water is displaced? (Consider Archimedes' principle.) Compare that to how much water is displaced by the anchor when it's just tossed into the water.

3. Aug 3, 2012

### jamesbiomed

The additional water displaced--would be equal in mass to the added anchor. Does this mean we could set Fnet y =0?

4. Aug 3, 2012

### Staff: Mentor

Yes, when the anchor is put on the boat, the additional water displaced equals the mass of the anchor.

What about when the anchor is just put in the water directly?
Not sure what you mean. For something in equilibrium, such as the floating boat, Fnet = 0.

5. Aug 3, 2012

### jamesbiomed

The mass of the water displaced by the anchor will equal the mass of the anchor for sure.

Okay, I wasn't thinking right about the boat being equilibrium.

I think knowing this, I should be able to conclude it.

Thanks a lot for the help!

6. Aug 3, 2012

### Staff: Mentor

Really? Why do you think that?

7. Aug 3, 2012

### pgardn

James this would mean the mass of an aluminum anchor would have the same mass as that of a lead anchor. A "water anchor" would have the same mass as the water it displaced.

You see where the good Doctor is leading you...

8. Aug 4, 2012

### AGNuke

The water displaced is equal to the VOLUME of the anchor.

Archimedes Principle, Fbuoyant = ρliquidVg