Is Work Done by the Sun in a Circular Earth Orbit?

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SUMMARY

The discussion centers on the work done by the gravitational force of the Sun on Earth in a perfectly circular orbit. It is established that no work is done by the gravitational force during a small displacement, as the centripetal force is perpendicular to the displacement, resulting in a cosine factor of zero. The misconception regarding the tangential component of the force is clarified, emphasizing that in a perfectly circular orbit, there is no tangential force acting on the Earth.

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Saraharris38
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Okay, this is not a homework question, but a conceptual question already answered in the book.

Problem: Suppose the Earth's orbit around the sun is perfectly circular. What is the work done by the gravitational force of the sun on the Earth through a small displacement over a small time interval?

Answer: No work is done

My problem:

I understand that the centripetal portion of the force does not do any work on the Earth through a small displacement because it is perpendicular and thus the cos factor is zero. However, doesn't the tangential portion of the force act (for very small displacements) essentially parallel to the displacement, and thus do a bit of work?

Thanks!
 
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Saraharris38 said:
However, doesn't the tangential portion of the force act (for very small displacements) essentially parallel to the displacement, and thus do a bit of work?
But there's no tangential component of the force--you are assuming a perfectly circular orbit.
 

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