Is Work Path Dependent with a Zero Total Displacement?

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Work is path dependent, meaning that even if an object returns to its starting point, work can still be done if a force acts on it during the motion. Total displacement being zero does not imply that no work has occurred; for instance, dragging an object across a rough surface involves work despite returning to the original position. The discussion clarifies that work is not a state function like energy, as it relies on the specific path taken. Therefore, work can be performed even when the total displacement is zero. Understanding the distinction between work and displacement is crucial in physics.
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Is work done if the total displacement is 0?

It doesn't matter what path the object took to get from A back to A, right? As long as it ends at A, then its zero work, correct?

So work IS NOT path dependent, it's a state function, like energy, right ?
 
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fiziksfun said:
Is work done if the total displacement is 0?
In general, yes.
fiziksfun said:
It doesn't matter what path the object took to get from A back to A, right? As long as it ends at A, then its zero work, correct?
No. In general even if the displacement is zero when a force acts on a moving object, work is done.
fiziksfun said:
So work IS NOT path dependent, it's a state function, like energy, right ?
Nope, work is path dependent.

For example, consider dragging a block across a rough surface for a distance of ten meters and then dragging it back to the same place you started. Did you do work on that block?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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