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Isobaric compression from isotherm to adiabat

  • Thread starter nlingraham
  • Start date
  • #1
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Homework Statement



The figure(Figure 1) shows a thermodynamic process followed by 150 mg of helium. Determine the pressure (in atm) at points 1, 2, and 3. Determine the temperature (in °C) at points 1, 2, and 3.

http://imgur.com/B7lwQ

n=.0375 mol
P1=3 atm
P2=1 atm
T1=971.85 k
T2=971.85 k
V1=1000 cm^3
V2=V3=3000 cm^3

Homework Equations



PV=nRT


The Attempt at a Solution



I'm only on the pressure part right now. From the given chart P1=3 atm. I used PV=nRT, and got that T1 and T2 are 971.85 K. With that, I used ideal gas law again to get that P2=1 atm. However, I don't know how to get the pressure at point 3 since I don't know the temperature at that point. It looks like it goes through an isobaric compression from the isotherm to the adiabat to me. Any help is appreciated.

(303000)(.001)=(.0375)(8.314)T, T1=T2=971.85 K

P(.003)=(.0375)(8.314)(971.85), P2=1 atm
 
Last edited:

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,230
31
From 1 to 3, the He goes through an adiabatic process such that

PVγ= constant

So you will have to use this to get P3
 
  • #3
16
0
Ok, I get the PVγ, where γ=5/3 since its a monatomic gas, but what exactly is the constant? Is that supposed to be nR?
 
  • #4
16
0
Ok, I think I got it. So it would be P2V2γ=P1V1γ and then just solve for P2
 
  • #5
16
0
Thank you for your help!
 

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